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bezimeni [28]
3 years ago
7

An airplane is traveling 835km/h in a direction 41.5 west of north. Find the components of the velocity vector in the northerly

and westernly directions. How far north and how far west has the plane traveled after 2.50h?
Physics
1 answer:
tatiyna3 years ago
3 0
<span>As the angle has been measured from north, the north component should be calculated with cosine and the west component should be calculated with sine: Vn = 835km/h*cos(41.5) =625 km/h Vw = 835km/h*sin(41.5) =553 km/h In order to calculate the distance travelled after 2.5 hours, we should use the uniform linear movement formula: d=v*t total distance (modulus of the distance)= 835km/h*2.5h=2088 km Or we can calculate each component (north and west): dn=625 km/h*2.5h=1563 km dw=553 km/h*2.5h=1383 km </span>
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A girl is sitting in a sled sliding horizontally along some snow (there is friction present).
prisoha [69]

Answer:

Ff = 159 [N]

Explanation:

Since in the problem give us two values of friction coefficient one static and the other dynamic, it is important to keep in mind that in order to solve this problem we must know the conditions in which the sled is located. We can read that the sled is in motion, in this way we use the dynamic coefficient of friction.

The friction force is calculated as the product of normal force, by the appropriate coefficient of friction value.

Ff = N * μ

Ff = 636 * 0.25

Ff = 159 [N]

6 0
3 years ago
There is a simple relationship between the energy for a photon of light Ephoton in units of eV (electron volts) and its waveleng
Eva8 [605]

Answer:

\lambda=620\ nm

E_p=1.9682\ eV

E_p=206.67\ eV is the photon energy of an x-ray

Explanation:

Given:

Energy of photon, E_p=2\ eV

Then according to given:

E_p=\frac{1240}{\lambda}

2=\frac{1240}{\lambda}

\lambda=620\ nm is the wavelength

Again,

Energy of photon, E_p=?

wavelength of the light, \lambda=630\ nm

E_p=\frac{1240}{630}

E_p=1.9682\ eV

<u>Now, photon energy for an x-ray:</u>

wavelength, \lambda=6\ nm

E_p=\frac{1240}{6}

E_p=206.67\ eV is the photon energy of an x-ray

3 0
3 years ago
The New England Merchants Bank Building in Boston is 152 m high. On windy days it sways with a frequency of 0.15Hz , and the acc
Minchanka [31]

Answer:

See answer below

Explanation:

Hi there,

I'm a bit late with this response, but I attached the work below.

Good luck with physics, have fun!

thanks,

4 0
3 years ago
Also need help with 20 &amp; 21 please
SSSSS [86.1K]
Number 20 is B and 21 is C
5 0
3 years ago
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The cockroach Periplaneta americana can detect a static electric field of magnitude 8.50 kN/C using their long antennae. If the
erica [24]

Answer:

0.235 nC

Explanation:

Given:

  • E = the magnitude of electric field = 8.50\ kN/C =8.50\times 10^{3}\ N/C
  • F = the magnitude of electric force on each antenna = 2.00\ \mu N =2.00\times 10^{-6}\ N
  • q = The magnitude of charge on each antenna

Since the electric field is the electric force applied on a charged body of unit charge.

\therefore E = \dfrac{F}{q}\\\Rightarrow q =\dfrac{F}{E}\\\Rightarrow q =\dfrac{2.00\times 10^{-6}\ N}{8.50\times 10^{3}\ N/C}\\\Rightarrow q =0.235\times 10^{-9}\ C\\\Rightarrow q =0.235\ nC

Hence, the value of q is 0.235 nC.

4 0
3 years ago
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