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Ipatiy [6.2K]
4 years ago
10

A ball is dropped from rest from the top of a 6.15-m-tall building, falls straight downward, collides in-elastically with the gr

ound, and bounces back. the ball loses 20.0% of its kinetic energy every time it collides with the ground. how many bounces can the ball make and still reach a windowsill that is 2.52 m above the ground?
Physics
1 answer:
Mashutka [201]4 years ago
5 0
I'm not sure

That is a hard question

Let me think...
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(a) Calculate the self-inductance (in mH) of a 55.0 cm long, 10.0 cm diameter solenoid having 1000 loops.
DedPeter [7]

Explanation:

(a) We have,

Length of solenoid, l = 55 cm = 0.55 m

Diameter of the solenoid, d = 10 cm

Radius, r = 5 cm = 0.05 m

Number of loops in the solenoid is 1000.

(a) The self inductance in the solenoid is given by :

L=\dfrac{\mu_o N^2A}{l}

A is area

L=\dfrac{4\pi \times 10^{-7}\times (1000)^2\times \pi (0.05)^2}{0.55}\\\\L=0.0179\ H\\\\L=17.9\ mH

(b) The energy stored in the inductor is given by :

E=\dfrac{1}{2}LI^2\\\\E=\dfrac{1}{2}\times 0.0179\times (19.5)^2\\\\E=3.4\ J

Hence, this is the required solution.

4 0
3 years ago
A spring does 5.0 J of work on a 0.10-kg ball bearing in a pinball machine. The ball's
lisov135 [29]

Answer:

10m/s

Explanation:

5 0
3 years ago
Apply the impulse-momentum relation and the work-energy theorem to calculate the maximum value of t if the cake is not to end up
loris [4]
Puto chupame el semen ok? right?
8 0
3 years ago
A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 11.1 rad/s in 2.99 s.(a) fi
elena55 [62]
The angular acceleration of a rotating object is given by
\alpha =  \frac{\omega_f - \omega_i}{\Delta t}
where
\omega_f is the final angular speed of the object
\omega_i is its initial angular speed
\Delta t is the time taken to accelerate

For the wheel in our problem, \omega_f=11.1 rad/s, \omega_i = 0 and \Delta t=2.99 s, so its angular acceleration is
\alpha= \frac{11.1 rad/s-0}{2.99 s}=3.71 rad/s^2
8 0
3 years ago
A student attaches a 20 ohm resistor to a battery and measures a current of 0.30 A. What is the voltage of the battery?
Sati [7]

Answer:6v

Explanation:

Current=0.30A

Resistance=20ohms

voltage=current x resistance

Voltage=0.30 x 20

Voltage=6v

4 0
3 years ago
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