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Paraphin [41]
3 years ago
5

Many carboxylic acids are much better known by their common names than by their systematic names. 2-Hydroxypropanoic acid (bette

r known as lactic acid, it is found in sour milk and is formed in the muscles during exercise). Provide a structural formula for lactic acid.

Chemistry
1 answer:
sdas [7]3 years ago
3 0

Answer:

  • CH₃ - CH - COOH

                  |

                  OH

  • The developed structural formula is also attached.

Explanation:

The IUPAC name, <em>2-hydroxypropanoic acid</em>, lets you predict the structural formula for <em>lactic acid</em>.

  • <em>2-hydroxy</em> means that there is a OH functional group attached to the second carbon atom of the chain.

  • <em>Propan</em> prefix means that the molecule has 3 carbon atoms.

  • <em>oic</em> suffix means that it is a carboxylic acid, this is it contains the COOH functional group.

Hence, in conclusion the structural form of lactic acid is:

  • C³H₃ - C²H - C¹OOH

                   |

                   OH

I used the superscripts just to show the number of the carbon atom in the chain.

The formal structural formula does not contain such superscripts it is just:

  • CH₃ - CH - COOH

                  |

                  OH

A more developed structural formula will show the distribution of the atoms in the space. I have also attached a picture with the developes structural formula.

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Hydrogen gas can be produced by reacting aluminum with sulfuric acid. how many moles of sulfuric acid are needed to completely r
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What is the name for the compound formed between nitrogen and magnesium. (show your work)
astra-53 [7]

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the compound formed between nitrogen and magnesium is Magnesium Nitride

7 0
2 years ago
2. (Exercise 4.1.6) A liquid adhesive consists of a polymer dissolved in a solvent. The amount of polymer in the solution is imp
Lilit [14]

Answer:

800 lb of pure solvent , 1700 lb of 20% solution and 500 lb of 10% solution will be mixed to form 3000 lb of 13 % solution .

Explanation:

3000 lb of 13% solution is required .

Total adhesive in weight = 3000 x .13 = 390 lb of adhesive

Available = 500 lb of 10% solution = 50 lb of adhesive

Rest = 390 - 50 = 340 lb required .

rest mass of solution = 3000 - 500 = 2500 lb

mass of adhesive required = 340 lb

Let the mass  of 20% required be V

mass of adhesive = .20 V

.20 V = 340

V = 1700

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So 800 lb of pure solvent , 1700 lb of 20% solution and 500 lb of 10% solution will be mixed to form 3000 lb of 13 % solution .

6 0
3 years ago
Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4
inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

M=\frac{n_{solute}}{V_{solution}}

So you can solve for the moles of the solute:

n_{solute}=M*V_{solution}

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

n_{solute}=1mol/L*1.5L=1.5mol

But this is just a supposition.

Regards.

4 0
3 years ago
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