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Paraphin [41]
3 years ago
5

Many carboxylic acids are much better known by their common names than by their systematic names. 2-Hydroxypropanoic acid (bette

r known as lactic acid, it is found in sour milk and is formed in the muscles during exercise). Provide a structural formula for lactic acid.

Chemistry
1 answer:
sdas [7]3 years ago
3 0

Answer:

  • CH₃ - CH - COOH

                  |

                  OH

  • The developed structural formula is also attached.

Explanation:

The IUPAC name, <em>2-hydroxypropanoic acid</em>, lets you predict the structural formula for <em>lactic acid</em>.

  • <em>2-hydroxy</em> means that there is a OH functional group attached to the second carbon atom of the chain.

  • <em>Propan</em> prefix means that the molecule has 3 carbon atoms.

  • <em>oic</em> suffix means that it is a carboxylic acid, this is it contains the COOH functional group.

Hence, in conclusion the structural form of lactic acid is:

  • C³H₃ - C²H - C¹OOH

                   |

                   OH

I used the superscripts just to show the number of the carbon atom in the chain.

The formal structural formula does not contain such superscripts it is just:

  • CH₃ - CH - COOH

                  |

                  OH

A more developed structural formula will show the distribution of the atoms in the space. I have also attached a picture with the developes structural formula.

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inessss [21]

Answer:

0.44316859040048207mol

Explanation:

7 0
2 years ago
In NMR if a chemical shift(δ) is 211.5 ppm from the tetramethylsilane (TMS) standard and the spectrometer frequency is 556 MHz,
Vika [28.1K]

Answer:

The answer is: 11759 Hz

Explanation:

Given: Chemical shift: δ = 211.5 ppm, Spectrometer frequency = 556 MHz = 556 × 10⁶ Hz

In NMR spectroscopy, the chemical shift (δ), expressed in ppm, of a given nucleus is given by the equation:

\delta (ppm) = \frac{Observed\,frequency (Hz)}{Frequency\,\, of\,\,the\,Spectrometer (MHz)} \times 10^{6}

\therefore Observed\,frequency (Hz)= \frac{\delta (ppm)\times Frequency\,\, of\,\,the\,Spectrometer (MHz)}{10^{6}}

Observed\,frequency= \frac{211.5 ppm \times 556 \times 10^{6} Hz}{10^{6}} = 11759 Hz

<u>Therefore, the signal is at 11759 Hz from the TMS.</u>

6 0
3 years ago
A certain gas occupies a volume of 26L when the applied pressure is 5.7atm. find the pressure in the system when the gas is comp
sergiy2304 [10]
P1 = 5.7atm V1 = 26L
P2 = ? V2 = 6.5 L

By Boyles Law,
P1V1 = P2V2
5.7 × 26 = P2 × 6.5
By solving,
P2 = 22.8atm.
8 0
3 years ago
How much space does a 246g box take up. Its density is listed at 3.2 g/cm3.
CaHeK987 [17]

Answer:

76.875 cm3

<h2>Explanation:</h2>

Since: Density = \frac{Mass}{volume\\}

Then: Volume = \frac{Mass}{Density\\}

The mass of the box = 246g

and the density = 3.2 g/cm3

Then: The volume = \frac{246}{3.2}

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4 0
3 years ago
g Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.71 g of ethane i
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Answer:

6.05g

Explanation:

The reaction is given as;

Ethane + oxygen --> Carbon dioxide + water

2C2H6 + 7O2 --> 4CO2 + 6H2O

From the reaction above;

2 mol of ethane reacts with 7 mol of oxygen.

To proceed, we have to obtain the limiting reagent,

2,71g of ethane;

Number of moles = Mass / molar mass = 2.71 / 30 = 0.0903 mol

3.8g of oxygen;

Number of moles = Mass / molar mass = 3.8 / 16 = 0.2375 mol

If 0.0903 moles of ethane was used, it would require;

2 = 7

0.0903 = x

x = 0.31605 mol of oxygen needed

This means that oxygen is our limiting reagent.

From the reaction,

7 mol of oxygen yields 4 mol of carbon dioxide

0.2375 yields x?

7 = 4

0.2375 = x

x = 0.1357

Mass = Number of moles * Molar mass = 0.1357 * 44 = 6.05g

8 0
3 years ago
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