Answer:
(4²πx2) + (8π x 4) = 201.061... OR 64π
<span>B. {x|–5 < x < 6} and</span>C. (–5, 6)
If you draw only 25 balls, you could draw the 25 odd-numbered balls. However, there will then be no odd-numbered balls left, so when you draw two more you will be guaranteed to get two even-numbered balls. Thus, the minimum is 25+2=27 balls.
I think its A please dont get mad if its wrong
<span>9, 12, 19, 30, ...
</span>formula for the nth term is;
<span>2n^2 + 3n - 10</span>
