Answer:
Angular speed of the bacteria motor is 1447rad/s
t = 4.342 × 10^-3 seconds
Explanation:
Hint: Do you remember circular motion in physics???
Okay, let's go
Given:
radius of 1.61 10-8 m
tangential speed at the rim of 2.33 10-5 m/s
Let's recall that angular velocity
ω = Vt/r
Where,
Vt = 2.33 10-5 m/s
r = 1.61 10-8 m
ω = ?
ω = 2.33 ×10-5 m/s = 1447rad/s
1.61 ×10-8 m
Angular speed of the bacteria motor is 1447rad/s
Let's find the elapsed time too
Since The angular velocity is said to be constant, there will be no acceleration (a = 0)
Using:
θ = ωot + (1/2at^2)
t = θ/ωo
(θ = 1 revolution or 2π rad, ωo = 1447rad/s)
t = (2π rad)/(1447 rad/s)
t = 4.342 × 10^-3 seconds
Genus and species i believ
Answer:
an exchange of homologous segments between homologous chromosomes.
Explanation:
Crossing over happens during meiosis, during this process the two homologous chromosomes cross over each other, resulting in the exchange of genetic information giving rise to a mixture parental genetic materials.
