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nadya68 [22]
3 years ago
9

Iron (Fe) reacts with copper sulfate (CuSO4) to form iron (II) sulfate. In this reaction, Cu2+ gains electrons to form Cu. Which

statement is true about this reaction? Fe(s) + CuSO4(aq) _ FeSO4(aq) + Cu(s)
Chemistry
1 answer:
Zanzabum3 years ago
6 0
Remember, OIL RIG 
Oxygen Is Loss of electrons 
Reduction Is Gain of electrons 

If something goes from + to - then it has gained electrons 
If something goes from neutral to - it has gained electrons 
If it goes from - to + is loses electrons 
If it goes from neutral to + it loses electrons 

If something is oxidised, it is a reducing agent 
If something is reduced, it is an oxidising agent 


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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A compound containing chromium, Cr; chlorine, Cl; and oxygen, O, is analyzed and found to be 33.6% chromium, 45.8% chlorine, and
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Answer

The empirical formula is CrO₂Cl₂

Explanation:

Empirical formula is the simplest whole number ratio of an atom present in a compound.

The compound contain, Chromium=33.6%

                                         Chlorine=45.8%

                                          Oxygen=20.6%

And the molar mass of Chromium(Cr)=51.996 g mol.

                 Chlorine containing molar mass (Cl)= 35.45    g mol.

                 Oxygen containing molar mass (O)=15.999  g mol.

Step-1

 Then,we will get,

Cr=\frac{1}{51.996} \times33.6=0.64 mol

Cl= \frac{1}{35.45} \times45.8=1.29 mol.

O=\frac{1}{15.99} \times=1.28 mol.

Step-2

Divide the mole value with the smallest number of mole, we will get,

Cr= \frac{0.64}{0.64} =1

Cl= \frac{1.29}{0.64} =2

O= \frac{1.28}{0.64} =2

Then, the empirical formula of the compound is CrO₂Cl₂ (Chromyl chloride)

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Explanation:

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Answer:

C. P = nRT

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Hope this helps :)

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