1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nadya68 [22]
3 years ago
9

Iron (Fe) reacts with copper sulfate (CuSO4) to form iron (II) sulfate. In this reaction, Cu2+ gains electrons to form Cu. Which

statement is true about this reaction? Fe(s) + CuSO4(aq) _ FeSO4(aq) + Cu(s)
Chemistry
1 answer:
Zanzabum3 years ago
6 0
Remember, OIL RIG 
Oxygen Is Loss of electrons 
Reduction Is Gain of electrons 

If something goes from + to - then it has gained electrons 
If something goes from neutral to - it has gained electrons 
If it goes from - to + is loses electrons 
If it goes from neutral to + it loses electrons 

If something is oxidised, it is a reducing agent 
If something is reduced, it is an oxidising agent 


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
You might be interested in
Explain the difference between a physical property and a chemical property
Eduardwww [97]
Physical property-  is an aspect of matter that can be observed or measured without touching changing it.

Chemical property- may only be observed by changing the chemical identity of a substance.

The difference would be that for physical property's you dont need to do anything to figure out what they are, but for chemical properties you need to change something to observe them.

5 0
3 years ago
1. (8pt) Using dimensional analysis convert 600.0 calories into kilojoules
Ivanshal [37]

Answer:

1. 2.510kJ  

2. Q = 1.5 kJ

Explanation:

Hello there!

In this case, according to the given information for this calorimetry problem, we can proceed as follows:

1. Here, we consider the following equivalence statement for converting from calories to joules and from joules to kilojoules:

1cal=4.184J\\\\1kJ=1000J

Then, we perform the conversion as follows:

600.0cal*\frac{4.184J}{1cal}*\frac{1kJ}{1000J}=2.510kJ

2. Here, we use the general heat equation:

Q=mC(T_2-T_1)

And we plug in the given mass, specific heat and initial and final temperature to obtain:

Q=236g*0.24\frac{J}{g\°C} (34.9\°C-8.5\°C)\\\\Q=1495.3J*\frac{1kJ}{1000J} \\\\Q=1.5kJ

Regards!

7 0
2 years ago
How can you use chemistry to enhance ground transportation vehicles and reduce pollution?
Svetradugi [14.3K]

Answer:

Ride a bike or walk. If you are only going a short distance, consider riding a bike or walking instead of driving. ...

Take public transit. ...

Carpool. ...

Avoid idling. ...

Use alternative fuels.

3 0
2 years ago
How many protons, neutrons, and electrons does a magnesium atom with a mass number of 25 contain?
guapka [62]
Protons: 12
Neutrons: 13
<span>Electrons: 12</span>
4 0
3 years ago
What must be the molarity of an aqueous solution of trimethylamine, (ch3)3n, if it has a ph = 11.20? (ch3)3n+h2o⇌(ch3)3nh++oh−kb
Stolb23 [73]

0.040 mol / dm³. (2 sig. fig.)

<h3>Explanation</h3>

(\text{CH}_3)_3\text{N} in this question acts as a weak base. As seen in the equation in the question, (\text{CH}_3)_3\text{N} produces \text{OH}^{-} rather than \text{H}^{+} when it dissolves in water. The concentration of \text{OH}^{-} will likely be more useful than that of \text{H}^{+} for the calculations here.

Finding the value of [\text{OH}^{-}] from pH:

Assume that \text{pK}_w = 14,

\begin{array}{ll}\text{pOH} = \text{pK}_w - \text{pH} \\ \phantom{\text{pOH}} = 14 - 11.20 &\text{True only under room temperature where }\text{pK}_w = 14 \\\phantom{\text{pOH}}= 2.80\end{array}.

[\text{OH}^{-}] =10^{-\text{pOH}} =10^{-2.80} = 1.59\;\text{mol}\cdot\text{dm}^{-3}.

Solve for [(\text{CH}_3)_3\text{N}]_\text{initial}:

\dfrac{[\text{OH}^{-}]_\text{equilibrium}\cdot[(\text{CH}_3)_3\text{NH}^{+}]_\text{equilibrium}}{[(\text{CH}_3)_3\text{N}]_\text{equilibrium}} = \text{K}_b = 1.58\times 10^{-3}

Note that water isn't part of this expression.

The value of Kb is quite small. The change in (\text{CH}_3)_3\text{N} is nearly negligible once it dissolves. In other words,

[(\text{CH}_3)_3\text{N}]_\text{initial} = [(\text{CH}_3)_3\text{N}]_\text{final}.

Also, for each mole of \text{OH}^{-} produced, one mole of (\text{CH}_3)_3\text{NH}^{+} was also produced. The solution started with a small amount of either species. As a result,

[(\text{CH}_3)_3\text{NH}^{+}] = [\text{OH}^{-}] = 10^{-2.80} = 1.58\times 10^{-3}\;\text{mol}\cdot\text{dm}^{-3}.

\dfrac{[\text{OH}^{-}]_\text{equilibrium}\cdot[(\text{CH}_3)_3\text{NH}^{+}]_\text{equilibrium}}{[(\text{CH}_3)_3\text{N}]_\textbf{initial}} = \text{K}_b = 1.58\times 10^{-3},

[(\text{CH}_3)_3\text{N}]_\textbf{initial} =\dfrac{[\text{OH}^{-}]_\text{equilibrium}\cdot[(\text{CH}_3)_3\text{NH}^{+}]_\text{equilibrium}}{\text{K}_b},

[(\text{CH}_3)_3\text{N}]_\text{initial} =\dfrac{(1.58\times10^{-3})^{2}}{6.3\times10^{-5}} = 0.040\;\text{mol}\cdot\text{dm}^{-3}.

8 0
3 years ago
Other questions:
  • How do you do problem bii??
    12·2 answers
  • Calculate the m/m% of casein in the milk sample:​
    9·1 answer
  • What provides clues about how igneous rocks were formed? A color B Texture C Luster D Streaks
    11·2 answers
  • A. the aldaric acid of d-allose is the same as the aldaric acid of which sugar?
    6·1 answer
  • Why nucleus of an atom is negatively charged?​
    15·1 answer
  • Insoluble substances can dissolve in all solvents. True or false
    14·1 answer
  • In need of help!!!!
    7·1 answer
  • What is the volume of a 25 g object with a density of 9.1 g/mL? please help me​
    6·1 answer
  • Helllllp meh pleaseeeeeee
    15·2 answers
  • If 0.400 moles CO and 0.400 moles O2 completely react how many grams of CO2 are produces?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!