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hichkok12 [17]
3 years ago
15

How hot is a supergiant star compared to our sun also the size

Chemistry
2 answers:
oee [108]3 years ago
8 0

Answer:

supergiant stars can have masses from 10 to 70 times greater than our sun, and when it comes to Brightness, some of them can be 30,000 times brighter than our sun. the temperature range of supergiant stars spans from around 3,450k to 20,000k.

Romashka-Z-Leto [24]3 years ago
5 0

Answer:

Stars several times more massive then the sun have a simpler, quicker, and more spectacular evolutionary sequence. Because super giants are so massive, the core temperature gets much hotter than in giants, so supergiants can fuse elements heavier than hydrogen and helium.

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¿Cuáles son las ventajas y desventajas entre la agricultura intensiva y la biológica?
SVEN [57.7K]

Answer:

La agricultura intensiva puede eliminar rápidamente los nutrientes del suelo, que generalmente se repara con fertilizantes. La agricultura ecológica normalmente se refiere a no transgénicos

producción y falta de fertilizantes y pesticidas más dañinos. Por lo general, los productos orgánicos se venden a un precio más alto a las personas que creen que los conservantes afectan su salud y bienestar. Los productos intensivos generalmente se venden en grandes cadenas de mercado para obtener grandes ganancias y, por lo general, las frutas transgénicas se pueden producir en casi todas las estaciones.

intensive agriculture can remove nutrients from the soil quickly which is usually remedied by fertilizer. Organic farming normally refers to non-gmo

produce and lack of more harmful fertilizers and pesticides. Usually the organic produce is sold for a higher price to people who believe the preservatives affect their health and well being. Intensive produce is usually sold in large market chains for great profit and usually gmo fruits can be produced in almost all seasons.

Explanation:

espero que esto ayude.

3 0
3 years ago
The relationships among which variable quantities are expressed by the ideal gas law equation?
Eva8 [605]

<u><em>The  variable quantities are expressed by the ideal gas law equation are; </em></u>

<u><em>pressure, volume, temperature, number of moles</em></u>

<u><em /></u>

This question is simply based on defining the ideal gas law.

  • Now, A gas is considered to ideal if its particles are so far from each other in such a manner that they don't exhibit any forces of attraction between themselves. Now, in real life this is not possible but under high temperatures and pressure, we can have something close to it and that's why ideal gas laws are very important.

  • This law states that states that the pressure, temperature, number of moles and volume of a gas are related to each other by the formula;

PV = nRT

Where;

P is pressure

V is volume

n is number of moles

T is temperature

R is ideal gas constant (This is fixed and not variable)

The  variable quantities are expressed by the ideal gas law equation are;

<em>pressure, volume, temperature, number of moles</em>

Read more at; brainly.in/question/5212853

8 0
3 years ago
Read 2 more answers
At a certain temperature, 0.760 mol SO3 is placed in a 1.50 L container. 2SO3(g) = 2SO2(g) + O2(g)At equilibrium, 0.130 mol O2 i
olganol [36]

Answer:

K_c=0.0867

Explanation:

Moles of SO₃ = 0.760 mol

Volume = 1.50 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.760}{1.50\ L}

[SO₃] = 0.5067 M

Considering the ICE table for the equilibrium as:

\begin{matrix} & 2SO_3_{(g)} & \rightleftharpoons & 2SO_2_{(g)} & + & O_2_{(g)}\\At\ time, t = 0 & 0.5067 &&0&&0 \\ At\ time, t=t_{eq} & -2x &&2x&&x \\----------------&-----&-&-----&-&-----\\Concentration\ at\ equilibrium:- &0.5067-2x&&2x&&x\end{matrix}

Given:    

Equilibrium concentration of  O₂ = 0.130 mol

Volume = 1.50 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.130}{1.50\ L}

[O₂] = x = 0.0867 M

[SO₂] = 2x = 0.1733 M

[SO₃] = 0.5067-2x = 0.3334 M

The expression for the equilibrium constant is:

K_c=\frac {[SO_2]^2[O_2]}{[SO_3]^2}  

K_c=\frac{(0.3334)^2\times 0.0867}{(0.3334)^2}

K_c=0.0867

5 0
3 years ago
Please Please Please Help Me In This Question!!!!
SVETLANKA909090 [29]
When converting Joules to Kilo-joules think like math kilo is 0.1 of 100 so 200 joules would equal 0.2 kilo-joules. Hope this helps ;)
7 0
3 years ago
How many grams of silver iodide (AgI) are produced from the reaction of 411.5 g
garri49 [273]
I don’t know but sorryyyyyy
6 0
2 years ago
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