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stepladder [879]
1 year ago
10

25. 0 ml of a 0. 100 m solution of NH3 is titrated with 0. 250m HCl. After 10. 0 ml of the hcl has been added, the resultant sol

ution is?
Chemistry
1 answer:
AveGali [126]1 year ago
5 0

Main Answer: The resultant solution will have 0.125M of HCl.

Explanation:

Given:

Volume of NH3  V1= 25ml = 0.025lit

Molar concentration of NH3  M1= 0.1M

It is titrated with HCl

Molar concentration of HCl M2= 0.25M

Volume of HCl  V2= ?ml

At equilibrium,

M1V1 = M2V2

V2 = M1V1/M2

V2 = (0.1*0.025)/0.25

V2= 0.01lit =0.01*1000 = 10ml

Number of moles = M2*V2 = 0.25 * 0.01 = 0.0025

Now 10ml of HCl is added.

then,

V2 = 10 + 10 = 20ml

Molar concentration of HCl = number of moles/Volume

                                               = 0.0025/0.02

                                               = 0.125M

The resultant solution will have 0.125M of HCl.

To know more about resultant solution, please visit:

brainly.com/question/20367152

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Dmitry_Shevchenko [17]

Answer:

1/360

Explanation:

let x = liters

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3 years ago
5. for the following measurements is expressed to three significant figures? a) 0.007 m b) 7077 mg c) 7.30 x 10^-7 km d) 0.070
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Iron reacts with oxygen to produce iron oxide rust this reaction is representative in an equation as to FE plus XO22FE203 identi
igomit [66]

The balanced equation :

4Fe + 3O₂⇒ 2Fe₂O₃

<h3>Further explanation</h3>

Given

Rust reaction

Required

Balanced equation

Solution

Reaction

Fe + O₂⇒ 2Fe₂O₃

For a simple equation where one of the reaction coefficients is known, we can immediately add the corresponding coefficient using the principle that the number of atoms of <em>the components in the reactants and products is the same. </em>

In the above reaction :

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3 0
3 years ago
Calculate how many moles of nh3 form when each quantity of reactant completely reacts?
anygoal [31]

3.6 moles NH_{3} required when each quantity of reactant completely reacts.

The ratio of the mole quantities of any two compounds present in a balanced chemical reaction is known as the mole ratio. A reaction's product yield can be predicted using mole ratios, as can the amount of reactant required to produce a specific amount of result.

The balanced chemical equation is :

3N_{2} H_{4}(l) → 4NH_{3}(g) + N_{2}(g)

Given is = 2.6 mol N_{2} H_{4}

As we see, 3 moles of N_{2} H_{4} reacts with  4 moles of NH_{3}.

Therefore,

n( NH_{3}) = n(  N_{2} H_{4} ) × \frac{4}{3}

n( NH_{3}) = 2.6mol^{*} \frac{4mol}{3mol}

n( NH_{3}) = 3.6 moles.

Therefores, 3.6 moles NH_{3} required when each quantity of reactant completely reacts.

Learn more about moles here;

brainly.com/question/20486415

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6 0
2 years ago
Need help on this please help
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