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stepladder [879]
10 months ago
10

25. 0 ml of a 0. 100 m solution of NH3 is titrated with 0. 250m HCl. After 10. 0 ml of the hcl has been added, the resultant sol

ution is?
Chemistry
1 answer:
AveGali [126]10 months ago
5 0

Main Answer: The resultant solution will have 0.125M of HCl.

Explanation:

Given:

Volume of NH3  V1= 25ml = 0.025lit

Molar concentration of NH3  M1= 0.1M

It is titrated with HCl

Molar concentration of HCl M2= 0.25M

Volume of HCl  V2= ?ml

At equilibrium,

M1V1 = M2V2

V2 = M1V1/M2

V2 = (0.1*0.025)/0.25

V2= 0.01lit =0.01*1000 = 10ml

Number of moles = M2*V2 = 0.25 * 0.01 = 0.0025

Now 10ml of HCl is added.

then,

V2 = 10 + 10 = 20ml

Molar concentration of HCl = number of moles/Volume

                                               = 0.0025/0.02

                                               = 0.125M

The resultant solution will have 0.125M of HCl.

To know more about resultant solution, please visit:

brainly.com/question/20367152

#SPJ4

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To check that the equation is balanced count how many atoms are present for each element in the reactant and product side. If they are the same before and after reaction for all elements, then the reaction is deemed balanced.

The atom counting for the equation is shown below:

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To determine the state of the substances, consider their solubility.

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<h3>LEARN MORE</h3>
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