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Xelga [282]
3 years ago
14

112 11X13 111 10 515 a. 106 B.92 c. 74 d. 88

Physics
1 answer:
nikitadnepr [17]3 years ago
3 0

Answer:

it 106

Explanation:

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Q5: An ice skater moving at 12 m/s coasts
ExtremeBDS [4]

u = 0.077

Explanation:

Work done by friction is

Wf = ∆KE + ∆PE

-umgx = ∆KE,. ∆PE =0 (level ice surface)

-umgx = KEf - KEi = -(1/2)mv^2

Solving for u,

u = v^2/2gx

= (12 m/s)^2/2(9.8 m/s^2)(95 m)

= 0.077

8 0
3 years ago
A stretched string has a mass per unit length of 5.00 g/cm and a tension of 10.0 N. A sinusoidal wave on this string has an ampl
8_murik_8 [283]

Answer:

0.12 mm ; 140.50 rad/m ; 628.32 rad/sec ; +

Explanation:

Given the wave equation of the form :

y(x, t) = ym sin(kx ± ωt)

Mas per unit length (u) = 5 g/cm = (5÷1000)kg / 0.01m) = 0.005kg/0.01m = 0.5kg/m

Tension, T = 10 N

Amplitude, A = 0.12 mm

Frequency, F = 100 Hz

Comparing with the general wave equation :

y = Asin(kx ± ωt)

A = amplitude = ym = 0.12 mm

2.) k = 2π / λ

Recall :

v = fλ

v = sqrt(T/u) = sqrt(10/0.5) = sqrt(20) = 4.472

λ = v/ f = 4.472 / 100 = 0.04472

Hence,

k = (2 * π) / 0.04472

k = 140.50 rad/m

3.) Angular frequency, ω

ω = 2πf = 2 * 3.14 * 100 = 628.32 rad/sec

4.) sign is +ve

Direction of wave propagation as given is in the negative x axis

4 0
2 years ago
A skier with a 65kg mass skies down a 30 degree incline hill. The coefficient of friction is 0.1. a. Draw a free body diagram. b
djyliett [7]
B is the answer! Because no one would be pushing the rock all the way down the hill it would just go down by itself by rolling!!



Hope i helped plz mark as brainlist and 5 star'!
6 0
4 years ago
Explain the necessity of smoothing the output voltage before applying it to a transistor
ra1l [238]

In simple words, smoothing can be defined as the circuit which is done to eliminate the ripple from the yield of a direct current power supply.

<u>Explanation:</u>

<u>Necessity of smoothing:</u>

  • Smoothing can be also applied in the form of a capacitor that acts to decrease or level out variations in a signal. And these capacitors are mostly used after power supply in voltage.
  • The yield DC voltage of a half-wave rectifier provided in the figure of a sinusoidal wave.
  • In a method to provide a constant DC voltage from a corrected AC source, a filter or smoothing circuit is required.

<u></u>

<u />

6 0
3 years ago
Perhaps to confuse a predator, some tropical gyrinid beetles(whirligig beetles) are colored by optical interference that is duet
gulaghasi [49]

Answer:

The grating spacing of the beetle is 1.078*10^{-6}m

Explanation:

The concept to solve this problem is relate to interference effect given in the Young's Slits. Here was demonstrated that the length of the side labelled \lambda is known as the path difference. The equation is given by,

n\lambda = dsin\theta

Where,

\lambda= wavelenght of light

N = a positive integer: 1,2,3...

\theta = Angle from the center of the wall to the dark spot

d= width of the slit

Replacing our values we have that for n=1,

dsin\theta = n\lambda

dsin(30)=(1)(539*10^{-9})

d=1.078*10^{-6}m

Therefore the grating spacing of the beetle is 1.078*10^{-6}m

6 0
3 years ago
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