Vf = vi + at
0m/s = 40m/s + a(0.025s)
a = -1600m/s^2
Fnet = ma
Fnet = (0.10kg)(-1600m/s^2)
Fnet = -160 N
hope that helps
It has to move through a distance over time.
Answer:
7560 Joules
Explanation:
= Mass of first car = 
= Mass of second car = 
= Initial Velocity of first car = 0.3 m/s
= Initial Velocity of second car = -0.12 m/s
v = Velocity of combined mass
As linear momentum of the system is conserved

Energy lost is

The Energy lost in the collision is 7560 Joules
The speed of the brick dropped by the builder as it hits the ground is 17.32m/s.
Given the data in the question;
Since the brick was initially at rest before it was dropped,
- Initial Velocity;

- Height from which it has dropped;

- Gravitational field strength;

Final speed of brick as it hits the ground; 
<h3>Velocity</h3>
velocity is simply the same as the speed at which a particle or object moves. It is the rate of change of position of an object or particle with respect to time. As expressed in the Third Equation of Motion:

Where v is final velocity, u is initial velocity, h is its height or distance from ground and g is gravitational field strength.
To determine the speed of the brick as it hits the ground, we substitute our giving values into the expression above.

Therefore, the speed of the brick dropped by the builder as it hits the ground is 17.32m/s.
Learn more about equations of motion: brainly.com/question/18486505
Answer:
B. 9.0 V
Explanation:
In parallel circuits, the voltage across each circuit is the same across each component, which is also equal to the total voltage of the power supplied. So in this case, the voltage across each resistor is still 9.0V.
The voltage only changes when the resistors can connected in series.