Answer:
"13.48 Kwhr" is the right solution.
Explanation:
The given values are:
Average rate of heat energy,
= 0.063 W/m²
Diameter,
= 8m
Efficiency of conversion,
= 50%
Now,
The area of hotspot will be:
⇒
On substituting the values, we get
⇒
⇒
⇒
Total heat generation rate will be:
⇒
hence,
The electricity generation capacity will be:
⇒
On substituting the values, we get
⇒
⇒
On converting into Kwhr, we get
⇒
Answer:
10.93 rad/s
Explanation:
If we treat the student as a point mass, her moment of inertia at the rim is
So the system moment of inertia when she's at the rim is:
Similarly, we can calculate the system moment of inertia when she's at 0.456 m from the center
We can apply the law of angular momentum conservation to calculate the post angular speed when she's 0.456m from the center:
Answer: 150 m
Explanation:
velocity = 22 m/s
t = 6.8 s
velocity =
distance = velocity × time
= 22 × 6.8
= 149.6 m
≈ 150 m
option C
Answer:
The value of each charge is 4.22 x 10⁻⁵ C
Explanation:
Given;
distance between the two identical charges, d = 2 m
the force of repulsion between these two charges, F = 4N
Apply Coulomb's law;
Therefore, the value of each charge is 4.22 x 10⁻⁵ C