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kvasek [131]
4 years ago
9

Two very small spheres are initially neutral and separated by a distance of 0.30 m. Suppose that 2.00 1013 electrons are removed

from one sphere and placed on the other. (a) What is the magnitude of the electrostatic force that acts on each sphere
Physics
1 answer:
GREYUIT [131]4 years ago
6 0

Answer:

The magnitude of the electrostatic force that acts on each sphere is 1.027 N

Explanation:

Given;

distance of separation of the two spheres, r = 0.3 m

number of electrons on the spheres = 2 x 10¹³ e

charges on each sphere, q = 2 x 10¹³ x 1.602 x 10⁻¹⁹ C = 3.204 x 10⁻⁶ C

According to coulomb's law;

F = \frac{kq^2}{r^2}

where;

F is the electrostatic force between the spheres

K is coulomb's constant = 9 x 10⁹ Nm²/c²

F = \frac{kq^2}{r^2} = \frac{9*10^9 *(3.204*10^{-6})^2}{0.3^2} = 1.027 \ N

Therefore, the magnitude of the electrostatic force that acts on each sphere is 1.027 N

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The energy of a photon of light is __________ proportional to its frequency and __________ proportional to its wavelength.
icang [17]

Answer:

D) directly, inversely

Explanation:

The energy of a photon of light is directly proportional to its frequency and inversely proportional to its wavelength.

Frequency is the number of waves that passes through a point per unit of time.

Wavelength is the is the distance between successive crests or troughs on a wave.

 Mathematically, frequency is related to wavelength and velocity using;

             Energy   =  h x f

                      where h is the Planck's constant

                                  f is the frequency

         

                   Since c  = f ∧

where f is the frequency of the wave

           ∧ is the wavelength of the wave

           c is the speed of light

So;

                 f  = c/∧

  Therefore;

                E  = \frac{h c}{wavelength}

From the equation, we see an inverse relationship between E and wavelength and a direct one with frequency.

           

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3 years ago
How many meters are in 32 kilometers
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Answer:

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3 years ago
two point charges of magnitude 4.0 μc and -4.0 μc are situated along the x-axis at x1 = 2.0 m and x2 = -2.0 m, respectively. wha
user100 [1]

The electric potential at the origin of the xy coordinate system is negative infinity

<h3>What is the electric field due to the 4.0 μC charge?</h3>

The electric field due to the 4.0 μC charge is E = kq/r² where

  • k = electric constant = 9.0 × 10 Nm²/C²,
  • q = 4.0 μC = 4.0 × 10 C and
  • r = distance of charge from origin = x₁ - 0 = 2.0 m - 0 m = 2.0 m

<h3>What is the electric field due to the -4.0 μC charge?</h3>

The electric field due to the -4.0 μC charge is E = kq'/r² where

  • k = electric constant = 9.0 × 10 Nm²/C²,
  • q' = -4.0 μC = -4.0 × 10 C and
  • r = distance of charge from origin = 0 - x₂ = 0 - (-2.0 m) = 0 m + 2.0 m = 2.0 m

Since both electric fields are equal in magnitude and directed along the negative x-axis, the net electric field at the origin is

E" = E + E'

= -2E

= -2kq/r²

<h3>What is the electric potential at the origin?</h3>

So, the electric potential at the origin is V = -∫₂⁰E".dr

= -∫₂⁰-2kq/r².dr

Since E and dr = dx are parallel and r = x, we have

= -∫₂⁰-2kqdxcos0/x²

= 2kq∫₂⁰dx/x²

= 2kq[-1/x]₂⁰

= -2kq[1/x]₂⁰

= -2kq[1/0 - 1/2]

= -2kq[∞ - 1/2]

= -2kq[∞]

= -∞

So, the electric potential at the origin of the xy coordinate system is negative infinity

Learn more about electric potential here:

brainly.com/question/26978411

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