All categories

3 years ago

What is potential difference

Physics

2 answers:

Gemiola [76]3 years ago

8 0

Definition: the difference of electrical potential between two points.
Hope it helps!

zepelin [54]3 years ago

7 0

Potential difference is difference of potential (between points).

You might be interested in

Un diapasón vibra a 140 [Hz] y la onda emitida por él se propaga con una rapidez de 340 m/s.Considerando lo anterior, se puede a

Gnom [1K]

The question is: A tuning fork vibrates at 140 [Hz] and the wave emitted by it propagates with a speed of 340 m / s. Considering the above, it can be correctly stated that the wavelength of the wave emitted by the tuning fork is

Answer: Wavelength of the wave emitted by the tuning fork is 2.43 m.

Explanation:

Given: Frequency = 140 Hz

Speed = 340 m/s

wavelength = ?

Formula used to calculate the wavelength is as follows.

$\lambda = \frac{v}{f}$

where,

$\lambda$ = wavelength

v = speed

f = frequency

Substitute the values into above formula.

$\lambda = \frac{v}{f}\\= \frac{340 m/s}{140 Hz} (1 Hz = 1 s^{-1})\\= 2.43 m$

Thus, we can conclude that wavelength of the wave emitted by the tuning fork is 2.43 m.

5 0

3 years ago

Heat transfer between two substances is affected by specific heat and the

IgorLugansk [536]

The correct answer is D. Amount of time and area of physical contact between the substances.

Explanation:

Heat transfer refers to the flow of thermal energy or heat between two or more objects. This process involves multiple factors and implies heat from the hottest object goes to the coldest one until there is an equilibrium. To begin, heat transfer depends on the amount of thermal energy in the objects because objects must have a different amount of thermal energy for heat to flow.

Besides this, the amount of energy that flows depends on the time and the contact between the substances of objects. Indeed, objects need to be in contact or close to each other for heat to transfer, and the time needs to be enough for the process to occur. For example, if you place a pot over the fire just for a few seconds it is likely the heat transferred is minimal, which does not occur if you leave the pot more time. At the same time if the pot is in close contact with fire more heat will be transferred.-

6 0

4 years ago

At a sports car rally, a car starting from rest accelerates uniformly at a rate of 5 m/s/s over a straight-line distance of 291

Bogdan [553]

Answer:

10.8 s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Acceleration (a) = 5 m/s/s

Distance travelled (s) = 291 m

Time (t) taken =?

We can calculate the time taken for the car to cover the distance as follow:

s = ut + ½at²

291 = 0 × t + ½ × 5 × t²

291 = 0 + 2.5 × t²

291 = 2.5 × t²

Divide both side by 2.5

t² = 291 / 2.5

t² = 116.4

Take the square root of both side

t = √116.4

t = 10.8 s

Thus, it will take the car 10.8 s to cover the distance.

8 0

3 years ago

An aquarium open at the top has 30-cm-deep water in it. You shine a laser pointer into the top opening so it is incident on the

Setler [38]

Answer:

You must add 8cm of water to the tank

Explanation:

In order to find how much the height is we will use the Snell Refraction law

This law relates the index of refraction of the water (n2), the index of refraction of the air (n1), the incidence angle relative to the vertical (theta1) and the refraction angle relative to the vertical (theta2) by using the next equation:

$(n1)*(sin(theta1))=(n2)*(sin(theta2))$

Then we will find the refraction angle relative to the vertical this way:

$(n1/n2)*(sin(theta1))=sin(theta2)$

$(1/1.33)*(sin(45))=sin(theta2)$

Then, theta2=32.12°

Now that we have this information we can imagine a triangle with a 30cm height and a 32.12° angle. This way we can find how much X is, this X will be the distance between the vertical line and the spot the beam hits the bottom, so we can use some trigonometry to find it, this way:

$tan(32.12)=(X/30cm)$

$X=(tan(32.12))*(30cm)$

Then, X=18.8cm, we can approximate it to 19cm

Once we have X we will add 5cm to it which is how much the beam needs to be moved, then the new X will be 24cm

Now, with the new horizontal distance we will find the new vertical distance, let´s call it Y, this way we will know how much water we must add to move the beam, then we will have a triangle with a vertical distance called Y, the same 32.12° angle will be used as we are still working with the air-water interface and a 19cm horizontal distance, then:

$tan(32.12)=(24cm/Y)$