What’s the velocity of an 11-kilogram object with 792 joules of kinetic energy?
2 answers:
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Given:
density of air at inlet,
density of air at inlet,
Solution:
Now,
(1)
where
A = Area of cross section
= velocity of air at inlet
= velocity of air at outlet
Now, using eqn (1), we get:
= 1.14
% increase in velocity = =114%
which is 14% more
Therefore % increase in velocity is 14%
Complete Question
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Answer:
The workdone is
Explanation:
From the question we are told that
The initial Volume is
The final volume is
The external pressure is
Generally the change in volume is
Substituting values we have
Generally workdone is mathematically represented as
W is negative because the working is done on the environment by the system which is indicated by volume increase
Substituting values
Now
Therefore
