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Andreyy89
3 years ago
8

A cylindrical conductor of length l and uniform area of cross section A has a resistance R. Another conductor of length 2l and r

esistance R of the same material must have the area of cross section.....................
Physics
2 answers:
Verizon [17]3 years ago
7 0

Answer:

2A

Explanation:

The resistivity ρ = RA/l. Let R₁ = R, A₁ = A and l₁ = l be the initial resistance, cross-sectional area and length of material. If our length now becomes l₂ = 2l, R₂ = new resistance = R, A₂ = new area = ?. Since resistivity is constant,

R₁A₁/l₁ = R₂A₂/l₂

A₂ = R₁A₁l₂/R₂l₁ = RA(2l)/Rl = 2A

A₂ = 2A

Our new area is twice the old area.

ella [17]3 years ago
6 0

Answer:

2A

Explanation:

The resistance of a wire can be defined as

R = ρL/A

Where,

ρ is Resistivity  - the factor in the resistance which takes into account the nature of the material is the resistivity

L is Length of the conductor

A is Area of cross section of the conductor.

R₁/R₂ = (L₁/L₂) × (A₂/A₁)  ----> rearranging it for A

A₂ = (R₁/R₂) × (L₂/L₁) × A₁  

A₂ = (R/R) × (2L/L) × A  

A₂ = 2A

Therefore, cross section area of another conductor must be 2A

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Describe how the three methods of thermal energy transfer may take place within the iguana’s enclosure.
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1) Freddy drives 4 miles east to his friend's house. He then travels 9 more miles east to the supermarket. Finally on his way ba
timurjin [86]

Answer:

<h3>B. 19miles</h3>

Explanation:

If Freddy drives 4 miles east to his friend's house. He then travels 9 more miles east to the supermarket. Finally on his way back home he out  of gas 6 miles after leaving the supermarket, the distance travel by fred will be the sup of all the distances he covered throughout the journey.

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8 0
3 years ago
Two boxers are fighting. Boxer 1 throws his 5 kg fist at boxer 2 with a speed of 9 m/s.
Sladkaya [172]

Answer:

0.001 s

Explanation:

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F=\frac{\Delta p}{\Delta t}

where

F is the force applied

\Delta p is the change in momentum

\Delta t is the time interval

The change in momentum can be written as

\Delta p=m(v-u)

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m is the mass

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So the original equation can be written as

F=\frac{m(v-u)}{\Delta t}

In this problem:

m = 5 kg is the mass of the fist

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Therefore, we can re-arrange the equation to solve for the time:

\Delta t=\frac{m(v-u)}{F}=\frac{(5)(0-9)}{-45,000}=0.001 s

4 0
3 years ago
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