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aliina [53]
3 years ago
6

At a sports car rally, a car starting from rest accelerates uniformly at a rate of 5 m/s/s over a straight-line distance of 291

m. How long (in seconds) did it take the car to travel the 291 m
Physics
1 answer:
Bogdan [553]3 years ago
8 0

Answer:

10.8 s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Acceleration (a) = 5 m/s/s

Distance travelled (s) = 291 m

Time (t) taken =?

We can calculate the time taken for the car to cover the distance as follow:

s = ut + ½at²

291 = 0 × t + ½ × 5 × t²

291 = 0 + 2.5 × t²

291 = 2.5 × t²

Divide both side by 2.5

t² = 291 / 2.5

t² = 116.4

Take the square root of both side

t = √116.4

t = 10.8 s

Thus, it will take the car 10.8 s to cover the distance.

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the electric field midway between two equal but opposite point charges is 573 n/c , and the distance between the charges is 16.0
saveliy_v [14]

The electric potential  between the two charges is 91.68 V.

<h3>Electric potential between the two charges</h3>

The electric potential  between the two charges is calculated as follows;

V = Ed

where;

  • V is electric potential
  • E is electric field
  • d is the distance of the charge

Substitute the given parameters and solve for electric potential,

V = 573 N/c x 0.16 m

V = 91.68 V

Thus, the electric potential  between the two charges is 91.68 V.

Learn more about electric potential here: brainly.com/question/26978411

#SPJ4

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1 year ago
Think more about the situation in the question above. If you picked a "good" thing, how might
solong [7]

your on here to lol we must be hella failing g

7 0
3 years ago
Penguin #1 travels at speed v=0.9 c relative to penguin #2. At the instant that both are at the origin, they synchronize their c
Alekssandra [29.7K]

Answer:

L = 0.44 [m]

Explanation:

Here we can use the Lorentz transformation related to length to solve it:

L=L_{0}\sqrt{1-\beta^{2}}

<u>Where</u>:

L₀ is the length of the moving reference frame (penguin #1)

L is the length of the fixed reference frame (penguin #2)

β is the ratio between v and c

<u>We know that v = 0.9c so we can find β.</u>

\beta = \frac{0.9c}{c}=0.9

L=1 [m]\sqrt {1-0.9^{2}} = 0.44 [m]

Therefore, the length of the meter stick of #1 observed by #2 is 0.44 m.

I hope it helps you!

6 0
4 years ago
Answers to question 2,3,4
Sati [7]

Answer:

OMG

these are sooooooo hard

Explanation:

5 0
3 years ago
Read 2 more answers
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