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Airida [17]
3 years ago
9

How can you change the negative emotions about math that you might be feeling to positive associations? (Answer in 175 words) th

ank you :)
Mathematics
1 answer:
Genrish500 [490]3 years ago
7 0
175... I can try my best. )) If your one of the many that don’t like math, just know your not the only person in the world with this feeling. Surprisingly, there are ways and methods that maybe with change your negative thoughts into positive thoughts about math. Try striving to be the best in the class, work the hardest. Your work will pay off and in the end, you’ll feel proud of what you’ve accomplished. If you’ve got some bad thoughts about an up coming test or quiz, study the entire week for that quiz/test.Make sure you know the material , so you can walk into math class feeling confident. Lastly, walk into math everyday with an open mind. Don’t get too stressed, and say to yourself “They’ve got to teach it to me first”. Also, always ask questions. If you don’t know what’s going on, always ask a question. There might be someone else wondering the same question. uhmmm this should get you going. if you need more help lmk
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Tasya [4]
Answer: maybe 20 cm
7 0
2 years ago
Miguel is a golfer, and he plays on the same course each week. The following table shows the probability distribution for his sc
aivan3 [116]

1) 4.55

2) Short hit

Step-by-step explanation:

1)

The table containing the score and the relative probability of each score is:

Score 3 4 5 6 7

Probability 0.15 0.40 0.25 0.15 0.05

Here we call

X = Miguel's score on the Water Hole

The expected value of a certain variable X is given by:

E(X)=\sum x_i p_i

where

x_i are all the possible values that the variable X can take

p_i is the probability that X=x_i

Therefore in this problem, the expected value of MIguel's score is given by:

E(X)=3\cdot 0.15 + 4\cdot 0.40 + 5\cdot 0.25 + 6\cdot 0.15 + 7\cdot 0.05=4.55

2)

In this problem, we call:

X = Miguel's score on the Water Hole

Here we have that:

- If the long hit is successfull, the expected value of X is

E(X)=4.2

- Instead, if the long hit fails, the expected value of X is

E(X)=5.4

Here we also know that the probability of a successfull long hit is

p(L)=0.4

Which means that the probabilty of an unsuccessfull long hit is

p(L^c)=1-p(L)=1-0.4=0.6

Therefore, the expected value of X if Miguel chooses the long hit approach is:

E(X)=p(L)\cdot 4.2 + p(L^C)\cdot 5.4 = 0.4\cdot 4.2 + 0.6\cdot 5.4 =4.92

In part 1) of the problem, we saw that the expected value for the short hit was instead

E(X)=4.55

Since the expected value for X is lower (=better) for the short hit approach, we can say that the short hit approach is better.

8 0
3 years ago
One hundred fifty people were surveyed and asked if they believed in UFOs, ghosts, and Bigfoot.
Ilya [14]

Answer:

this ven diagram is 4 u lol

Step-by-step explanation:

5 0
2 years ago
3. Find two possible lengths for CD if C, D, and E
Kaylis [27]

Given :

C, D, and E  are col-linear, CE = 15.8 centimetres, and DE=  3.5 centimetres.

To Find :

Two possible lengths for CD.

Solution :

Their are two cases :

1)

When D is in between C and E .

.                   .           .

C                  D          E

Here, CD = CE - DE

CD = 15.8 - 3.5 cm

CD = 12.3 cm

2)

When E is in between D and C.

.       .                .

D      E              C

Here, CD = CE + DE

CD = 15.8 + 3.5 cm

CD = 19.3 cm

Hence, this is the required solution.

3 0
3 years ago
A mother has two children whose ages differ by 5 years. The sum of the squares of their ages is 97. The square of the​ mother's
svetoff [14.1K]

Answer:

41 years old.

Step-by-step explanation:

Let x represent age of younger child.

We have been given that a mother has two children whose ages differ by 5 years. So the age of older child would be x+5.

The sum of the squares of their ages is 97. We can represent this information in an equation as:

x^2+(x+5)^2=97

Let us solve for x.

x^2+x^2+10x+25=97

2x^2+10x+25-97=0

2x^2+10x-72=0

Divide both sides by 2:

x^2+5x-36=0

x^2+9x-4x-36=0

x(x+9)-4(x+9)=0

(x+9)(x-4)=0

(x+9)=0 ; (x-4)=0

x=-9 ; x=4

Since age cannot be negative, therefore, age of younger child is 4 years.

Age of older child would be x+5\Rightarrow4+5=9

Therefore, the age of older child would be 9 years.

We have been given that the square of the​ mother's age can be found by writing the squares of the​ children's ages one after the other as a​ four-digit number.

Square of 4: 4^2=16

Square of 9: 9^2=81.

Square of mother's age: 1681

To find mother's age, we need to take positive square root of 1681 as:

\sqrt{1681}=41

Therefore, the mother is 41 years old.

4 0
3 years ago
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