3 years ago

In which of the following situations would it NOT be wise to estimate?

Physics

1 answer:

ipn [44]3 years ago

5 0

Medicine to a patient. That should be calculated based on weight, strength/dosage and possibly other factors

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3 years ago

Two balls of radius 2.00 mm have a separation between their centers of 5.33 cm. The same electric charge is placed on both balls

AlekseyPX

Answer:

Charges, $q_1=q_2=4.03\ \mu C$

Explanation:

Given that,

Radius of the balls is 2 mm

The force of repulsion acting on the balls, F = 2.75 N

The separation between the spheres, d = 5.33 cm = 0.0533 m

The force of repulsion between charges is given by :

$F=\dfrac{kq^2}{d}$

$q^2=\dfrac{Fd}{k}$

$q^2=\dfrac{2.75 \times 0.0533 }{9\times 10^9}$

$q^2=1.62\times 10^{-111}\ C$

$q=4.03\times 10^{-6}\ C$

$q=4.03\ \mu C$

So, the charge on the spheres is $q=4.03\ \mu C$ . Hence, this is the required solution.

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3 years ago