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Gnom [1K]
2 years ago
13

What does the stomach acid have in protein digestion

Physics
1 answer:
castortr0y [4]2 years ago
5 0
It contains protease which is the enzyme that breaks down protein
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The attractive electrostatic force between the point charges +8.44 ✕ 10-6 and q has a magnitude of 0.961 n when the separation b
d1i1m1o1n [39]
The electrostatic force between two charges Q1 and q is given by
F=k_e  \frac{Q_1 q}{r^2}
where 
ke is the Coulomb's constant
Q1 is the first charge
q is the second charge
r is the distance between the two charges

Re-arranging the formula, we have
q= \frac{F r^2}{k_e Q_1}
and since we know the value of the force F, of the charge Q1 and the distance r between the two charges, we can calculate the value of q:
q= \frac{(0.961 N)(0.67 m)^2}{(8.99 \cdot 10^9 N m^2 C^{-2})(+8.44\cdot 10^{-6}C)}=5.69 \cdot 10^{-6} C

And since the force is attractive, the two charges must have opposite sign, so the charge q must have negative sign.
6 0
3 years ago
Which of the following represents thermal energy transfer through radiation
Bogdan [553]

C. since the the heat from the heater is going to the child in <u>waves</u>, it’s<u> radiating </u>

3 0
3 years ago
Explain why it is easier to climb a mountain on a zigzag path rather than one straight up the side.
GaryK [48]
Although a zig zag pattern going up a mountain means you walk further, the incline of the slope is a lot less so you don't have to work as hard.
8 0
3 years ago
What question can a student BEST answer when comparing and contrasting the models?
OverLord2011 [107]

Answer:

A

Explanation:

4 0
2 years ago
Please Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
arsen [322]

Answer:

Given that

speed u=4*10^6 m/s

electric field E=4*10^3 N/c

distance b/w the plates d=2 cm

basing on the concept of the electrostatices

now we find the acceleration b/w the plates  to find the horizontal distance traveled by the electron when it hits the plate.

acceleration a=qE/m=1.6*10^{-19}*4*10^3/9.1*10^{-31} =0.7*10^{15}=7*10^{14} m/s

now we find the horizontal distance traveled by electrons hit the plates

horizontal distance

X=u[2y/a]^{1/2}

=4*10^6[2*2*10^{-2}/7*10^{14}]^{1/2}

=3*10^{-2}= 3 cm

5 0
3 years ago
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