The volume of chlorine gas measured at STP will be liberated by a current of 2.5 A flowing for a period of 1.8 hours through an aqueous solution of AgCl is 1.88 litre.
<h3>What is Faraday's law ?</h3>
According to Faraday's Law , During Electrolysis , The amount of substance liberated at the cathode or anode is directly proportional to the electricity that is passed through the cell.
The reaction taking place at anode is:
2Cl → Cl₂ +2e −
The total charge is calculated as
Q=I×t= 2.5×1.8×60×60 coulomb
Q = 16200 coulomb
The amount of chlorine liberated by passing 16200 coulomb of electric charge
= 16200/(2*96500)
= 0.084 mole
Volume of Cl₂ at STP is
1 mole at STP has 22.4 L of Gas
0.084 mole of Cl₂ at STP will be equal to 22.4 *0.084 = 1.88 litre of Cl₂
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Answer:
the third one because oceans don't affect the weather
Explanation:
Energy levels are considered orbitals.
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<u>Answer:</u> The molar mass of the given unknown compound is 50.5 g/mol.
<u>Explanation:</u>
To calculate the volume of water, we use the equation given by ideal gas, which is:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
or,
![PV=\frac{m}{M}RT](https://tex.z-dn.net/?f=PV%3D%5Cfrac%7Bm%7D%7BM%7DRT)
where,
P = pressure of sample = 1.00 atm
V = volume of sample = 2010 mL = 2.010 L (Conversion factor: 1 L = 1000 mL)
m = Given mass of unknown compound = 2.73 g
M = Molar mass of unknown compound = ? g/mol
R = Gas constant = ![0.0820\text{ L atm }mol^{-1}K^{-1}](https://tex.z-dn.net/?f=0.0820%5Ctext%7B%20L%20atm%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D)
T = temperature of sample = ![180^oC=[180+273]K=453K](https://tex.z-dn.net/?f=180%5EoC%3D%5B180%2B273%5DK%3D453K)
Putting values in above equation, we get:
![1.00atm\times 2.010L=\frac{2.73g}{M}\times 0.0820\text{ L atm }mol^{-1}K^{-1}\times 453K\\\\V=50.45g/mol](https://tex.z-dn.net/?f=1.00atm%5Ctimes%202.010L%3D%5Cfrac%7B2.73g%7D%7BM%7D%5Ctimes%200.0820%5Ctext%7B%20L%20atm%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D%5Ctimes%20453K%5C%5C%5C%5CV%3D50.45g%2Fmol)
Rounding off to 3 significant figures, we get the molar mass to be 50.5 g/mol.
Hence, the molar mass of the given unknown compound is 50.5 g/mol.