1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Illusion [34]
3 years ago
8

Please answer! I will mark you as brainlist! ​

Chemistry
1 answer:
blagie [28]3 years ago
7 0

Answer:

a) no

b) no

c) yes

d) yes

Explanation:

You might be interested in
Limestone is used to make cement and mortar. <br> a. True <br> b. False
marusya05 [52]
The awnser is true maybe
8 0
3 years ago
Five gases combined in a gas cylinder have the following partial pressures: 3.00 atm (N2), 1.80 atm (O2), 0.29 atm (Ar), 0.18 at
levacccp [35]
In order to solve the total pressure that is exerted by the gases, we need to use the Dalton's Law of Partial pressures. These are the calculations that you need to find out the total amount of pressure exerted to the gases:

3.00atm (N2) + 1.80atm (O2) + 0.29atm (Ar) + 0.18atm (He) + 0.10atm (H),
add up all of that, and the answer would turn out to be: 5.37atm.
8 0
3 years ago
Read 2 more answers
A pea plant has two dominant alleles for plant height – tall. We say that this plant is?:
Irina-Kira [14]
I think the answer is codominant??
3 0
3 years ago
Can someone please answer this?
Amanda [17]

Answer:-

0.229 L

Explanation:-

Molar mass of AgBr = 107.87 x 1 + 79.9 x 1

=187.77 grams mol-1

Mass of AgBr = 150 grams

Number of moles of AgBr = 150 grams / 187.77 gram mol-1

= 0.8 mol

The balanced chemical equation is

NaBr (aq) + AgNO3 (aq)--> AgBr(s) + NaNO3(aq)

From the equation we can see that

1 mol of AgBr is produced from 1 mol of AgNO3.

∴ 0.8 mol of AgBr is produced from 1 x 0.8 / 1 = 0.8 mol of AgNO3.

Strength of AgNO3 = 3.5 M

Volume of AgNO3 required = Number of moles / strength

= 0.8 moles / 3.5

=0.229 L

8 0
3 years ago
A sample of gas occupies a volume of 61.5 mL . As it expands, it does 130.1 J of work on its surroundings at a constant pressure
Lesechka [4]

Answer:

the final volume of the gas is V_2 = 1311.5 mL

Explanation:

Given that:

a sample gas has an initial volume of 61.5 mL

The workdone = 130.1 J

Pressure = 783 torr

The objective is to determine the final volume of the gas.

Since the process does 130.1 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.

Converting the external pressure to atm ; we have

External Pressure P_{ext}:

P_{ext} = 783 \ torr \times \dfrac{1 \ atm}{760 \ torr}

P_{ext} = 1.03 \ atm

The workdone W = P_{ext}V

The change in volume ΔV= \dfrac{W}{P_{ext}}

ΔV = \dfrac{130.1 \ J  \times \dfrac{1 \ L  \ atm}{ 101.325 \ J}  }{1.03 \ atm }

ΔV = \dfrac{1.28398717 }{1.03  }

ΔV = 1.25 L

ΔV = 1250 mL

Recall that the initial  volume = 61.5 mL

The change in volume V is \Delta V = V_2 -V_1

-  V_2= -  \Delta V  -V_1

multiply through by (-), we have:

V_2=   \Delta V+V_1

V_2 =  1250 mL + 61.5 mL

V_2 = 1311.5 mL

∴ the final volume of the gas is V_2 = 1311.5 mL

5 0
3 years ago
Other questions:
  • Is glue a suspension colloid or solution?
    10·2 answers
  • These to particles are found in the center of an atom blank and blank
    5·1 answer
  • The chemical formula tells the types of atoms and how many of each are contained in a compound. Please select the best answer fr
    14·1 answer
  • True or false atoms of a given element will have the same mass
    9·1 answer
  • Which element is oxidized in the following reaction: 2FeCl₂ + Cl₂→2FeCl₃ if Fe goes from + 2 to +3 and Cl goes from 0 to −2?
    5·1 answer
  • Guys the semester is about to end and i still got so much hw to do plaease help.
    14·1 answer
  • You observe mothballs disappearing in cabinets. What do you think is the reason for this? Do all substances behave like mothball
    5·1 answer
  • Explain what the purpose of a gene is!!!!<br><br> *20*
    13·2 answers
  • The diameter of a circle is 17 cm. Find its circumference in terms of \piπ.
    5·1 answer
  • Describe and explain the trend in atomic a.radius within the group.Explain the difference between the size of b.the atoms and th
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!