Answer:
a.2.5x 10^3 m/s
b.mr=48kg/s
Explanation:
A rocket is moving away from the solar system at a speed of 7.5 ✕ 103 m/s. It fires its engine, which ejects exhaust with a speed of 5.0 ✕ 103 m/s relative to the rocket. The mass of the rocket at this time is 6.0 ✕ 104 kg, and its acceleration is 4.0 m/s2. What is the velocity of the exhaust relative to the solar system? (B) At what rate was the exhaust ejected during the firing?
velocity of the exhaust relative to the solar system
velocity of the rocket -velocity of the exhaust relative to the rocket.
7.5 ✕ 103 m/s-5.0 ✕ 103 m/s
2.5x 10^3 m/s
. b we will look for the thrust of the rocket
T=ma
T=6.0 ✕ 104 kg*4.0 m/s2
T=2.4*10^5N
f=mass rate *velocity of the exhaust
T=2.4*10^5N=mr*5.0 ✕ 10^3 m/s
mr=2.4*10^5N/5.0 ✕ 10^3
mr=48kg/s
