Answer:
Explanation:
Dear Student, this question is incomplete, and to attempt this question, we have attached the complete copy of the question in the image below. Please, Kindly refer to it when going through the solution to the question.
To objective is to find the:
(i) required heat exchanger area.
(ii) flow rate to be maintained in the evaporator.
Given that:
water temperature = 300 K
At a reasonable depth, the water is cold and its temperature = 280 K
The power output W = 2 MW
Efficiency
= 3%
where;



However, from the evaporator, the heat transfer Q can be determined by using the formula:
Q = UA(L MTD)
where;

Also;




LMTD = 4.97
Thus, the required heat exchanger area A is calculated by using the formula:

where;
U = overall heat coefficient given as 1200 W/m².K

The mass flow rate:

Answer:
90 degrees
Explanation:
the answer is 90 because angle a has a square on the angle which means it is 90 degrees
Answer:
<h2>8.0995×10^-21 kgms^-1</h2>
Explanation:
Mass of proton :

Speed of Proton:

Linear Momentum of a particle having mass (m) and velocity (v) :

Magnitude of momentum :

Frome equation (2), magnitude of linear momentum of the proton :

no, work is = force * distance or displacement