Answer:
The speed of the car before it began to skid is 47.56 m/s.
Explanation:
We can use kinematics to solve this problem.
We are given three known variables:
- Δx = 290 m
- a = -3.90 m/s²
- v = 0 m/s (final velocity is 0 m/s because the car skids to a stop).
We can use this kinematic equation to <u><em>solve</em></u><em> for the initial velocity</em>, v₀.
Substitute the known variables into the equation.
- (0)² = v₀² + 2(-3.9)(290)
- 0 = v₀² - 2262
- 2262 = v₀²
- <u>v₀ = 47.56 m/s</u>
The speed of the car before it began to skid is 47.46 m/s.
Answer:
16.87 m/s
Explanation:
To find the speed of the car at the top, when the normal force is equal the gravitational force, we just need to equate both forces:
is the centripetal acceleration in the loop:
So we have that:
So, using the gravity = 9.81 m/s^2 and the radius = 29 meters, we have:
The speed of the car is 16.87 m/s at the top.
Answer:
Momentum is the product of a moving object's mass and velocity . ... When two objects collide the total momentum before the collision is equal to the total momentum after the collision (in the absence of external forces). This is the law of conservation of momentum. It is true for all collisions.
Explanation:
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