Answer:
The final image relative to the converging lens is 34 cm.
Explanation:
Given that,
Focal length of diverging lens = -12.0 cm
Focal length of converging lens = 34.0 cm
Height of object = 2.0 cm
Distance of object = 12 cm
Because object at focal point
We need to calculate the image distance of diverging lens
Using formula of lens
![\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bv%7D%3D%5Cdfrac%7B1%7D%7Bf%7D-%5Cdfrac%7B1%7D%7Bu%7D)
![\dfrac{1}{v}=\dfrac{1}{-12}-\dfrac{1}{-12}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bv%7D%3D%5Cdfrac%7B1%7D%7B-12%7D-%5Cdfrac%7B1%7D%7B-12%7D)
![v=\infty](https://tex.z-dn.net/?f=v%3D%5Cinfty)
The rays are parallel to the principle axis after passing from the diverging lens.
We need to calculate the image distance of converging lens
Now, object distance is ∞
Using formula of lens
![\dfrac{1}{v}=\dfrac{1}{34}-\dfrac{1}{\infty}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bv%7D%3D%5Cdfrac%7B1%7D%7B34%7D-%5Cdfrac%7B1%7D%7B%5Cinfty%7D)
![v=34](https://tex.z-dn.net/?f=v%3D34)
The image distance is 34 cm right to the converging lens.
Hence, The final image relative to the converging lens is 34 cm.