Answer : The concentration of solution is, 8.53 M.
Explanation :
As we are given, 45.0 mass % solution of ethanol in water that means 45.0 g of ethanol present in 100 g of solution.
First we have to calculate the volume of solution.
Now we have to calculate the molarity of solution.
Mass of = 45.0 g
Volume of solution = 114.5 mL
Molar mass of = 46.07 g/mole
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Now put all the given values in this formula, we get:
Therefore, the concentration of solution is, 8.53 M.
Answer:
B) CH3(CH2)10CO2H
Explanation:
Hello,
In this case, we define amphipathic as a compound having both a hydrophilic and a hydrophobic part, for that reason, the hydrophilic part will be water-soluble (polar) whereas the hydrophobic does not (nonpolar). In such a way, some functional groups such as hydroxyl and carboxyl tend to be polar by cause of the presence of O-H bonds whereas long-carboned chains tend to be nonpolar by cause of the presence of C-H and C-C bonds.
Therefore, since A) CH3CH2OH (ethanol) and D) CH3CO2H (acetic acid) are short-carboned chains with polar groups they are largely hydrophilic whereas C) CH3(CH2)10CH3 (dodecane) is highly nonpolar, we sum up that only B) CH3(CH2)10CO2H (dodecanoic acid or lauric acid) is amphoteric as it has a long-charboned part (nonpolar) and a water-soluble part (polar).
Best regards.
Explanation:
solution 1) homogeneous
2) do not scatter light
3) cannot be separated by filtration
Colloids 1) heterogeneous
2) scatter light
3) cannot be separated by filtration
suspension 1) heterogeneous
2) may either scatter light or be opaque
3) can be separated by filtration
Electronic configure = [He} 1s₂ , 2s₂ , 2p₂