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s344n2d4d5 [400]
3 years ago
13

Project managers and their teams must keep in mind the effects of any project on the interests and needs of the entire system or

organization instead of focusing on the immediate concerns of the project. True or false?
Physics
1 answer:
amm18123 years ago
6 0

Answer:True

Explanation:

True

Even though it is easier to concentrate on the urgent and sometimes specific issues of a given project, project managers and all other personnel must bear in mind the influence of any project on the wants and needs of the entire system or organization.

A Project manager must perform following duties

  • Planning Project resources
  • Lead the team
  • Time management
  • Budget
  • Documentation            
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Large numbers of ribosomes are present in cells that specialize in producing which molecules?
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Answer:

Protein molecules

Explanation:

Ribosomes are the cell organelles that are responsible for the synthesis of protein in the cell. Proteins are the fundamental building blocks and help in repair and damage of cell in the body.

Ribosome is a complex which is made up of protein and RNA. Ribosomes can be found floating within the cytoplasm or attached to the endoplasmic reticulum.

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When a fork is placed in a hot piece of lasagna, thermal energy is transferred up the fork by
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<span>fast-moving particles colliding with slow-moving particles</span>
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If there are 20 waves in a 5-second time frame, what is the frequency?
creativ13 [48]
Your answer would be 0.20 Hz
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3 years ago
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A 0.600 m long pendulum is used to determine the acceleration due to gravity on a distant planet. If 20 complete oscillation are
givi [52]

Answer :

Explanation :

It is given that,

length of pendulum, l = 0.6 m

Number of oscillation, n = 20

time, t = 35.5 seconds

so, Time period, T=\dfrac{t}{n}

T=\dfrac{35.5s}{20}

we know that the time period of pendulum is given by

T=2\pi\sqrt{\dfrac{l}{g}}

g=\dfrac{4\pi^2l}{T^2}

g=\dfrac{4\times(3.14)^2\times 0.6 \times (20)^2}{(35.5s)^2}

g=7.51\ m/s^2

or

g=7.52\ m/s^2

6 0
3 years ago
A 62 kg skier is moving at 6.5 m/s on frictionless horizontal snow-covered plateau when she encounters a rough patch 3.50 m long
Degger [83]

Answer:

(A). The work done by friction in crossing the patch is -637.98 J.

(B). The speed of skier is 10.57 m/s.

Explanation:

Given that,

Mass of skier = 62 kg

Speed = 6.5 m/s

Length = 3.50 m

Coefficient kinetic friction = 0.30

Height = 2.5 m

(A) we need to calculate the work done by friction in crossing the patch

Using formula of work done

W=-\mu mg\times l

Put the value into the formula

W=-0.30\times62\times9.8\times3.50

W=-637.98\ J

The work done by friction in crossing the patch is -637.98 J.

(B) we need to calculate the speed of skier

Using conservation of energy

K.E_{i}+U_{i}-W_{friction}=K.E_{f}+U_{f}

\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2+U_{f}

Final potential energy is zero

So, \dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}v_{1}^2+gh-\mu gl

Put the value into the formula

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}\times6.5^2+9.8\times2.5+0.30\times9.8\times3.50

v_{2}=\sqrt{2\times55.915}

v_{2}=10.57\ m/s

The speed of skier is 10.57 m/s.

Hence,  (A).The work done by friction in crossing the patch is -637.98 J.

(B).The speed of skier is 10.57 m/s.

6 0
3 years ago
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