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3 years ago

An object that is in motion is *

Physics

1 answer:

Luba_88 [7]3 years ago

4 0

Answer:

An object is said to be in motion when it changes its place with time and respect to its surrounding.

Explanation:

Hope this helps :)

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Is knocking dominoes newton's 1st law ?

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No because Newton’s first law is inertia

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2 years ago

If the absolute pressure of gas is 550.280 kPa, its gauge pressure is

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pressure absolute = pressure gage + pressure atmosphere

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3 years ago

A steam turbine at an electric power plant delivers 4500 kW of power to an electrical generator that converts 95 percent of this

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3 years ago

A metal ball has a net charge of 4.5x10-7 C

netineya [11]

a) the number of protons is $2.81\cdot 10^{12}$ more than the electrons

b) $4.69\cdot 10^{-15} kg$

Explanation:

The net electric charge on the ball is

$Q=+4.5\cdot 10^{-7}C$

This electric charge is given by the algebraic sum of the charge of the protons and of the charge of the electrons.

The charge of one proton is:

$q_p =+e= +1.6\cdot 10^{-19}C$

While the charge of one electron is

$q_e = -e=-1.6\cdot 10^{-19}C$

So the net charge on the metal ball will be given by

$Q=N_p q_p + N_e q_e = (N_p -N_e)e$

where

$N_p$ is the number of protons

$N_e$ is the number of electrons

So we find:

$N_p-N_e=\frac{Q}{e}=\frac{4.5\cdot 10^{-7}}{1.6\cdot 10^{-19}}=2.81\cdot 10^{12}$

This means that the number of protons is $2.81\cdot 10^{12}$ more than the electrons.

In this case, we want to make the ball neautral, so we have to remove a net charge of Q' such that the new charge is zero:

$Q-Q'=0$

This implies that the charge that we must remove is

$Q'=Q=4.5\cdot 10^{-7}C$

To do that (and to make the ball losing mass at the same time), we have to remove protons, since they have positive charge.

The number of protons that must be removed is:

$N_p = \frac{Q'}{q_p}=\frac{4.5\cdot 10^{-7}}{1.6\cdot 10^{-19}}=2.81\cdot 10^{12}$

The mass of one proton is

$m_p = 1.67\cdot 10^{-27}kg$

Therefore, the total mass that must be removed from the ball is

$M=m_p N_p = (1.67\cdot 10^{-27})(2.81\cdot 10^{12})=4.69\cdot 10^{-15} kg$

6 0

2 years ago

A 45kg skater and a 60kg skater are standing still, holding hands on frictionless ice. They push away from each other in opposit

frutty [35]

Answer:

The 60 kg skater is traveling at 2.63 m/s in the opposite direction from the 45 kg skater.

Explanation:

The velocity of the 60 kg skater can be found by conservation of linear momentum:

$P_{i} = P_{f}$

$m_{a}v_{i_{a}} + m_{b}v_{i_{b}} = m_{a}v_{f_{a}} + m_{b}v_{f_{b}}$ (1)

Where:

$m_{a}$ : is the mass of the first skater = 45 kg

$m_{b}$ : is the mass of the second skater = 60 kg

$v_{i_{a}}$ : is the initial speed of the first skater = 0 (he is standing still)

$v_{i_{b}}$ : is the initial speed of the second skater = 0 (he is standing still)

$v_{f_{a}}$ : is the final speed of the first skater = 3.5 m/s

$v_{f_{b}}$ : is the final speed of the second skater =?

By replacing the above values into equation (1) and solving for $v_{f_{b}}$ we have:

$0 = m_{a}v_{f_{a}} + m_{b}v_{f_{b}}$

$v_{f_{b}} = \frac{-m_{a}v_{f_{a}}}{m_{b}} = \frac{-45 kg*3.5 m/s}{60 kg} = -2.63 m/s$

The minus sign is because the 60 kg skater is moving in the opposite direction from the other skater.

Therefore, the 60 kg skater is traveling at 2.63 m/s in the opposite direction from the 45 kg skater.

I hope it helps you!

4 0

2 years ago

An object that is in motion is *​

An object that is in motion is *