My best answer would be E<span>ukaryotic</span>
6 m/s
This type of collision is a <u>Inelastic collision </u>
Explanation:
We begin by finding the momentum of the initial train car;
Remember that momentum is given by the formulae mass (kg) * velocity (m/s)
Therefore;
Momentum = 6000 * 10
= 60,000 kg⋅m/s
The other car has zero momentum because;
4000 * 0
= 0
When the two train cars collide, the total momentum will be;
60,000 + 0 = 60,000
Therefore to find the velocity, well use the same formulae;
p = mv whereby;
p – momentum
m – mass
v – velocity
60,000 = (6000 + 4000) * v
v = 60,000 / 10,000
v = 6
= 6 m/s
This is an elastic collision because we are assuming that no energy is lost in the collision. Most collisions, however, are not elastic but rather inelastic. In inelastic collision some of the kinetic energy is lost to the environment in some other form of energy such as heat energy.
Learn More:
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Answer:
seven(7) different gametes can be produced
Answer:
The answer is C.
Explanation:
Net Primary Productivity is a term that is used to express the difference between CO2 that is taken in by the plant with photosynthesis minus CO2 that the plant releases.
The two forest sites given in the example may not have the same biodiversity and the same species of plants so we can't be sure of option B.
Again for the same reasons, we can't be sure of option D because we do not know the specific plant species in each forest since they are in different areas.
Option A can be ruled out for the same reasons, the lack of information about the forest sites, since we do not know the death rate of the plants in either of the forests.
Option C can be true because forest A has a higher net primary productivity rate which can be an indication of lower respiratory activity hence lower CO2 production, resulting in the given higher net primary productivity.
I hope this answer helps.
Answer:
The selenium particles when coated on paper towels were extremely effective and continuously inhibited (about a 90% reduction) the growth of gram-positive bacteria including S. aureus and S. epidermidis after 24, 48, or 72 hours.