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Anarel [89]
2 years ago
12

George Tomlin, RMA, has been working for several years in a specialty practice. He applies for a position closer to his home wit

h better hours and more pay. This office, however, sees patients with a variety of illnesses. For the first time since he graduated from college, he is encountering words and procedures with which he is not familiar. What is the best way for George to review his basic medical terminology? What should George do when he encounters a new word? What are some good ways for him to learn the new vocabulary for his new position?"
Chemistry
2 answers:
Semenov [28]2 years ago
6 0

For George Tomlin, the best way to review the basic medical terminologies and methods is by visual as well as by auditory ways.

  • George can read the words carefully by going through them in <u>books or from online resources.</u>
  • He can listen carefully the words in online lectures and tutorials and understand the meaning of the terminologies.

When George encounters a new word :

  • he can look up for the meaning of the word in the <u>medical textbooks or from any online sources.</u>
  • he can understand the meaning by discussing with his colleagues.
  • the new words has its roots, abbreviations, suffixes and prefixes in a <u>close proximity which makes the terminology easy</u> and also provides quick reference.

Some of the best ways for George to learn the new vocabulary for the new position are :

  • George can breakdown the words in such a way that <u>helps him to memorize the terminology less and understand more.</u>
  • Learn more in details about the origin and structure of the medical terms and discuss more often with his colleagues.

Learn More :

brainly.com/question/15010232

pentagon [3]2 years ago
6 0

Answer:

George Tomlin can make some flashcards, this method really works because the human brain learns by visual cues, looking at the word to recall the definition can help train your brain for memorization.He can also record himself, simply speaking and hearing medical terminology out load can also help you learn. One simple trick is to record yourself saying these medical terms and their definitions. The act of recording them will create aural flashcards. Listening to your recording will help you remember the words when you come across them in your reading. Another good tip would be memorizing the root words. Medical terminology is based on Latin and Greek root words. Understanding the word parts will help you understand complex medical terms. Often knowing part of a word will help you figure out the meaning of the entire word. For instance, knowing the “branch” is the root for terms related to the respiratory system, makes it easier to understand that “bronchial” or “bronchitis” is also related to the lungs or breathing.

Explanation:

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Which element has this electron configuration? <br> astatine<br> bromine<br> chlorine<br> fluorine
oksano4ka [1.4K]
Unfortunately you did not specify the electronic configuration in the question, however since one of the answers must be a halogen, i took the liberty to attach an image with the configuration (both the simple numeric and spdf form) for all the halogen and all you have to do is match the electronic configuration you have in your question to the one in the table attached and you can then deduce the answer.

Hope this helps.

7 0
3 years ago
Read 2 more answers
Calculate the percent by volume of a solution that has 75 mL of solute dissolved in 375 mL of solution. Show your work and round
Mandarinka [93]

Answer:

The answer is 20 % V/V

Explanation:

We use this formula for calculate the %V/V:

%V/V= (ml solute/ml solution) x 100= (75ml/375 ml)x 100 = 20 % V/V

<em>The% V / V represents the amount of ml of solute dissolved in 100 ml of solution</em>

7 0
3 years ago
Equal moles of H2, N2, O2, and He are placed into separate containers at the same temperature. Assuming each gas behaves ideally
lbvjy [14]

Answer:

They would all exhibit the same pressure.

Explanation:

Since the same number of mole of each gas is placed in different containers, it means the gas will occupy the same volume.

Now, the gases were observed at the same temperature. This means they will all have the same pressure as their volume is the same.

Now we can further understand this by doing a simple calculation as follow:

Assumptions:

For H2:

Number of mole (n) = 1 mole

Volume (V) = 22.4L

Temperature (T) = 298K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure =..?

PV = nRT

Divide both side V

P = nRT /V

P = 1 x 0.0821 x 298 / 22.4

P = 1 atm

Therefore, H2 has a pressure of 1 atm.

For N2:

Number of mole (n) = 1 mole

Volume (V) = 22.4L

Temperature (T) = 298K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure =..?

PV = nRT

Divide both side V

P = nRT /V

P = 1 x 0.0821 x 298 / 22.4

P = 1 atm

Therefore, N2 has a pressure of 1 atm

For O2:

Number of mole (n) = 1 mole

Volume (V) = 22.4L

Temperature (T) = 298K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure =..?

PV = nRT

Divide both side V

P = nRT /V

P = 1 x 0.0821 x 298 / 22.4

P = 1 atm

Therefore, O2 has a pressure of 1 atm

For He:

Number of mole (n) = 1 mole

Volume (V) = 22.4L

Temperature (T) = 298K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure =..?

PV = nRT

Divide both side V

P = nRT /V

P = 1 x 0.0821 x 298 / 22.4

P = 1 atm

Therefore, He has a pressure of 1 atm.

From the above illustrations we can see that the gases have the same pressure since they have the same number of mole, volume and were observed at the same temperature.

4 0
3 years ago
7. Calculate the amount of energy required heat 100.g to <br> H2O(s) changes to H2O(l) at 0°C
Brrunno [24]

Answer:

33300J

Explanation:

Given parameters:

Mass of ice  = 100g

Unknown:

Amount of energy = ?

Solution:

This is a phase change process from solid to liquid. In this case, the latent heat of melting of ice is 3.33 x 10⁵ J/kg.

 So;

            H  = mL

m is the mass

L is the latent heat of melting ice

  Now, insert the parameters and solve;

            H = mL

 mass from gram to kilogram;

            100g gives 0.1kg

  H = 0.1 x 3.33 x 10⁵ = 33300J

8 0
2 years ago
Find percent yield:
saveliy_v [14]

<u>Answer:</u> The percent yield of the reaction is 91.8 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For B_5H_9 :</u>

Given mass of B_5H_9 = 4.0 g

Molar mass of B_5H_9 = 63.12 g/mol

Putting values in equation 1, we get:

\text{Moles of }B_5H_9=\frac{4g}{63.12g/mol}=0.0634mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 10.0 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{10g}{32g/mol}=0.3125mol

The chemical equation for the reaction of B_5H_9 and oxygen gas follows:

2B_5H_9+12O_2\rightarrow 5B_2O_3+9H_2O

By Stoichiometry of the reaction:

12 moles of oxygen gas reacts with 2 moles of B_2H_5

So, 0.3125 moles of oxygen gas will react with = \frac{2}{12}\times 0.3125=0.052mol of B_2H_5

As, given amount of B_2H_5 is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

12 moles of oxygen gas produces 5 moles of B_2O_3

So, 0.3125 moles of oxygen gas will produce = \frac{5}{12}\times 0.3125=0.130moles of water

Now, calculating the mass of B_2O_3 from equation 1, we get:

Molar mass of B_2O_3 = 69.93 g/mol

Moles of B_2O_3 = 0.130 moles

Putting values in equation 1, we get:

0.130mol=\frac{\text{Mass of }B_2O_3}{69.63g/mol}\\\\\text{Mass of }B_2O_3=(0.130mol\times 69.63g/mol)=9.052g

To calculate the percentage yield of B_2O_3, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of B_2O_3 = 8.32 g

Theoretical yield of B_2O_3 = 9.052 g

Putting values in above equation, we get:

\%\text{ yield of }B_2O_3=\frac{8.32g}{9.052g}\times 100\\\\\% \text{yield of }B_2O_3=91.8\%

Hence, the percent yield of the reaction is 91.8 %

6 0
3 years ago
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