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Anarel [89]
3 years ago
12

George Tomlin, RMA, has been working for several years in a specialty practice. He applies for a position closer to his home wit

h better hours and more pay. This office, however, sees patients with a variety of illnesses. For the first time since he graduated from college, he is encountering words and procedures with which he is not familiar. What is the best way for George to review his basic medical terminology? What should George do when he encounters a new word? What are some good ways for him to learn the new vocabulary for his new position?"
Chemistry
2 answers:
Semenov [28]3 years ago
6 0

For George Tomlin, the best way to review the basic medical terminologies and methods is by visual as well as by auditory ways.

  • George can read the words carefully by going through them in <u>books or from online resources.</u>
  • He can listen carefully the words in online lectures and tutorials and understand the meaning of the terminologies.

When George encounters a new word :

  • he can look up for the meaning of the word in the <u>medical textbooks or from any online sources.</u>
  • he can understand the meaning by discussing with his colleagues.
  • the new words has its roots, abbreviations, suffixes and prefixes in a <u>close proximity which makes the terminology easy</u> and also provides quick reference.

Some of the best ways for George to learn the new vocabulary for the new position are :

  • George can breakdown the words in such a way that <u>helps him to memorize the terminology less and understand more.</u>
  • Learn more in details about the origin and structure of the medical terms and discuss more often with his colleagues.

Learn More :

brainly.com/question/15010232

pentagon [3]3 years ago
6 0

Answer:

George Tomlin can make some flashcards, this method really works because the human brain learns by visual cues, looking at the word to recall the definition can help train your brain for memorization.He can also record himself, simply speaking and hearing medical terminology out load can also help you learn. One simple trick is to record yourself saying these medical terms and their definitions. The act of recording them will create aural flashcards. Listening to your recording will help you remember the words when you come across them in your reading. Another good tip would be memorizing the root words. Medical terminology is based on Latin and Greek root words. Understanding the word parts will help you understand complex medical terms. Often knowing part of a word will help you figure out the meaning of the entire word. For instance, knowing the “branch” is the root for terms related to the respiratory system, makes it easier to understand that “bronchial” or “bronchitis” is also related to the lungs or breathing.

Explanation:

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ser-zykov [4K]
The formula of chalcopyrite is CuFeS₂.
The molar mass of chalcopyrite   - 183.5 g/mol
The mass of Cu in 1 mol of chalcopyrite is - 63.5 g
When 183.5 g of chalcopyrite is mined, the mass of Cu obtained - 63.5 g
So if 63.g of Cu is needed mass of chalcopyrite required - 183.5 g 
Then to gain 370 g of pure Cu - mass of chalcopyrite needed -183.5/63.5 x 370
therefore mass of chalcopyrite to be mined - 1069.21 g 

4 0
4 years ago
Which two trends increase when one moves across a period from left to right?
Sophie [7]

Answer is: a) ionization energy and electronegativity.

1) The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).  

Barium, potassium and arsenic are metals (easily lost valence electrons), chlorine is nonmetal (easily gain electrons).

Alkaline metals (far left in Periodic table) have lowest ionizations energy and easy remove valence electrons (one electron), earth alkaline metals (next right to alkaline metals) have higher ionization energy than alkaline metals, because they have two valence electrons.  

Nonmetals are far right in the main group and they have highest ionization energy, because they have many valence electrons.  

2) Electronegativity (χ) is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.  

Atoms with higher electronegativity attracts more electrons towards it, electrons are closer to that atom.  

Nonmetals hava higher electronegativity than metals and metalloids.

3) The atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.


6 0
3 years ago
Read 2 more answers
The diagram is a model of one way that materials move into a cell.
Vlad [161]

Answer:

B. The cell membrane surrounds particles outside the cell.

Explanation:

The last step is when the cell membrane completely surrounds particles outside the cell.

This process is often known as endocytosis.

  • endocytosis is the process whereby a cell ingests materials by engulfing them using the cell membrane.
  • In this process, the cell membrane completely covers the food.
8 0
3 years ago
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a sample of ammonia liberates 5.66 kj of heat as it solidifies at its melting point . what is the mass of the sample?
Reil [10]
The correct answer for the question that is being presented above is this one: "<span>16.728 g."</span>

Given that 
ΔHsolid = -5.66 kJ/mol.
This means that 5.66 kJ of heat is released when 1 mole of NH3 solidifies 

When 5.57 kJ of heat is released
amount of NH3 solidifies = 5.57/5.66 = 0.984 moles 

<span>molar mass of NH3 = 17 g/mole </span>
<span>1 mole of NH3 = 17 g </span>
So, 0.984 moles of NH3 = 17 X 0.984 = 16.728 g
7 0
3 years ago
The Ksp of yttrium iodate, Y(IO3)3 , is 1.12×10−10 . Calculate the molar solubility, s , of this compound.
torisob [31]

Answer:

1.427x10^-3mol per L

Explanation:

Y(IO_{3} )_{3} ---- Y^{3+} +IO_{3} ^{3-}

I could use ⇌ in the math editor so I used ----

from the question each mole of Y(IO3)3 is dissolved  and this is giving us a mole of Y3+ and a mole of IO3^3-

Ksp = [Y^3+][IO3-]^3

So that,

1.12x10^-10 = [S][3S]^3

such that

1.12x10^-10 = 27S^4

the value of s is 0.001427mol per L

= 1.427x10^-3mol per L

so in conclusion

the molar solubility is therefore 1.427x10^-3mol per L

3 0
3 years ago
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