Answer:
1.1724 g.
Explanation:
- Firstly we need to calculate the percentage of pure MgSO₄ in (MgSO₄.7H₂O).
- If we have 1.0 mol of MgSO₄.7H₂O, then we will have the the mass of its molecular mass.
The molecular mass of 1.0 mol (MgSO₄.7H₂O) = 246.4 g/mol.
The molecular mass of pure MgSO₄ = 120.366 g/mol.
The molecular mass of 7(H₂O) = 7(18.0 g/mol) = 126.0 g/mol.
∴ The mass % of pure MgSO₄ = [(mass of pure MgSO₄)/(mass of MgSO₄.7H₂O)] x 100 = [(120.366 g/mol)/(246.4 g/mol)] x 100 = 48.85%.
∴ the quantity of pure MgSO₄ = (mass of MgSO₄.7H₂O)(% of MgSO₄/100) = (2.4 g)(48.85/100) = 1.1724 g.
If too much of Na2Co3 is added to a particular chemical reaction, there will be a shortage of the other reactant which is supposed to react with the Na2Co3 and this will leads to excess production of the product. Stoichiometric should always be used to obtain information about the appropriate quantities of chemicals that should be used during chemical reactions.
Answer:
H+ ----- Br-
H+ ----- Cl-
O₋₋ -----2H++
CH3 ----- O- ------ H+
Explanation:
Dipole moment occurs when there is bonding between a very strong electronegative element and hydrogen atom.
Electronegative elements are the element which attract electrons towards themselves, (that is they have strong affinity for electrons).
Generally, group 7 elements (Fluorine, Chlorine, Bromine, Iodine) of the periodic table are highly electronegative
Factually, finland has the least amount of air pollution at only a 90.68 EPI score
Answer:
Clothing
Explanation:
keeps man warm and keeps man relatively dry