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Phoenix [80]
2 years ago
12

In a fission reaction of U-235, there was a release of 9.20 × 1011 kJ of energy. What amount of mass in kilograms would have bee

n lost? Recall that c = 3 × 108 m/s.
1.02 × 10-2
1.02 × 10-5
1.02 × 109
8.28 × 10-2
8.28 × 1022
Chemistry
2 answers:
Hatshy [7]2 years ago
3 0
<span>e = mc^2 
 
m = e / c^2 

Plug in your numbers in the appropriate units.
</span><span>m=1.02 × 10^-5

pulled from another response, hope it helps</span>
Aleonysh [2.5K]2 years ago
3 0
The answer is 1.02 x 10-5 B on plato
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A gas container has an initial temperature of 348 K with an unknown pressure. When the temperature changes to 506 K the pressure
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Answer:

1.06 atm

Explanation:

We are given the following variables to work with:

Initial pressure (P1): unknown

Initial temperature (T1): 348 K

Final temperature (T2): 506 K

Final pressure (P2): 1.55 atm

We are asked to find the initial pressure (P1). We want to choose a gas law equation that relates initial pressure and temperature to final pressure and temperature. Gay-Lussac's law does this:

\frac{P_{1}}{T_1} =\frac{P_{2}}{T_2} \\

We can rearrange the law algebraically to solve for P_{1}.

{P_{1}} =\frac{(T_1)(P_{2} )}{T_2} \\

Substitute your known variables and solve:

{P_{1}} =\frac{(348 K)(1.55 atm )}{506 K} \\ = 1.06 atm

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