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3 years ago

In a fuel cell there is direct conversion of mechanical energy into electricity.

Chemistry

1 answer:

rewona [7]3 years ago

5 0

Answer:

Explanation:

A fuel cell uses both hydrogen and oxygen as fuels. At the cathode oxygen is reduced to water according to the equation

O2+4H^+ +4e ------>2H2O

And hydrogen is oxidized at the anode:

2H2------>4H^+ +4e

Fuel cells produce only water as a by product hence they are environment friendly

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Which federal agency makes sure federal wildlife laws are followed?

goldfiish [28.3K]

Answer:

us fish and wildlife service

Explanation:

the 2nd choice

8 0

3 years ago

Read 2 more answers

ClO3− Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. Show t

Tresset [83]

Answer:

See explanation

Explanation:

The overall charge on ClO3− is shown on the image attached to this answer. If we calculate the formal charges on each atom in the structure, we will notice that one oxygen atom has a formal charge of -1 while all other atoms have a formal charge of zero.

This gives the compound an overall charge of -1 as shown in the image attached to this answer. This is the correct Lewis structure for the compound ClO3− .

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3 years ago

an electric current causes water to be transformed into hydrogen and oxygen gasses a physical change or a chemical change

Natalija [7]

Physical change because ther is force which is the electric current

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3 years ago

A chemist mixes 75.0 g of an unknown substance at 96.5°C with 1,150 g of water at 25.0°C. If the final temperature of the system

AleksAgata [21]

To do this problem it is necessary to take into account that the heat given by the unknown substance is equal to the heat absorbed by the water, but considering the correct sign:

$-m\cdot c_e\cdot \Delta T = m_w\cdot c_e_w\cdot \Delta T_w$

Clearing the specific heat of the unknown substance:

$c_e = \frac{m_w\cdot c_e_w\cdot \Delta T_w}{m\cdot \Delta T} = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot (37.1 - 25.0)^\circ C}{75\ g\cdot (37.1 - 96.5)^\circ C}$

$c_e = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot 12.1^\circ C}{75\ g\cdot (-59.4)^\circ C} = \bf 13.07\frac{J}{g\cdot ^\circ C}$

6 0

3 years ago

Assume that 300 J of heat is added to 3.00g of water originally at 23°C. what would be the final temperature of the water? The

Iteru [2.4K]

Answer:

47C

Explanation:

Recall the equation for specific heat:

q = mcΔT

300 = 3 x 4.184 x (T - 23)

T = 47

3 0

3 years ago