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Andrej [43]
2 years ago
13

When 1,250^3/4 is written in simplest radical form, which value remains under the radical?

Physics
2 answers:
GaryK [48]2 years ago
7 0

Answer:

125\sqrt[4]{8}

Explanation:

A number of the form

a^{\frac{m}{n}}

can be re-written in the radical form as follows:

\sqrt[n]{a^m}

In this problem, we have:

a = 1,250

m = 3

n = 4

So, if we apply the formula, we get

1,250^{\frac{3}{4}}=\sqrt[4]{(1,250)^3}

Then, we can rewrite 1250 as

1250 = 2\cdot 5^4

So we can rewrite the expression as

=\sqrt[4]{(2\cdot 5^4)^3}=5^3 \sqrt[4]{2^3}=125\sqrt[4]{8}

seraphim [82]2 years ago
7 0

Answer: The value remains under the radical is 8.

Explanation:

Given that,

1250^{\frac{3}{4}}

We know that,

a^{\frac{x}{n}}=n\sqrt{a^x}

Here, n = integer number

n is greater than x.

a = real number

Therefore,

1250^{\frac{3}{4}}=\sqrt[4]{1250}^3

1250^{\frac{3}{4}}=\sqrt[4]{2.5^{4}}^3

1250^{\frac{3}{4}}=5^3\sqrt[4]{2}^3

1250^{\frac{3}{4}}=125\sqrt[4]{8}

Hence, The value remains under the radical is 8.

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Virty [35]

Answer:

it does use it at doppler

Explanation:

My dad told me the hes a cop so yw

5 0
2 years ago
A 15-kg ball is tossed up into the air. The ball is 2 meters off the ground traveling 4 m/s. What is the potential energy? A. 29
Sladkaya [172]

Answer: 0j

Explanation:

At that point potential energy is zero and kinetic energy is maximum.. P. E=mgh=0

7 0
3 years ago
A juggler throws a bowling pin straight up with an initial speed of 8.20 m/s. How much time elapses until the bowling pin return
tensa zangetsu [6.8K]

Answer:

1.68 s

Explanation:

From newton's equation of motion,

a = (v-u)/t.................................. Equation 1

Making t the subject of the equation

t =(v-u)g............................. Equation 2

Where t = time taken for the bowling pin to reach the maximum height, v = final velocity bowling pin, u = initial velocity of the bowling pin, g = acceleration due to gravity.

Note: Taking upward to be negative and down ward to be positive,

Given: v = 0 m/s ( at the maximum height), u = 8.20 m/s, g = -9.8 m/s²

t = (0-8.20)/-9.8

t = -8.20/-9.8

t = 0.84 s.

But,

T = 2t

Where T = time taken for the bowling pin to return to the juggler's hand.

T = 2(0.84)

T = 1.68 s.

T = 1.68 s

7 0
3 years ago
Convert 68852 millijoules into Calories. (Write your answer in the decimal form. Do not include units in your answer).
alex41 [277]

Answer: 68852 millijoules = 16.46 calories

Explanation:

Given;

Convert 68852 millijoules to calories.

1 calorie = 4.184J = 4184millijoules

Therefore,

1 millijoule = 1/4184 calories

68852 millijoule = 68852 × 1/4184 calories

= 16.46 calories

6 0
2 years ago
A 2000 kg roller coaster is at the top of a loop with a radius of 24 m. If its speed is 18 m/s at this point, what force does it
levacccp [35]

Answer:

46620\ \text{N}

Explanation:

m = Mass of roller coaster = 2000 kg

r = Radius of loop = 24 m

v = Velocity of roller coaster = 18 m/s

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

Normal force at the point will be

N-mg=\dfrac{mv^2}{r}\\\Rightarrow N=\dfrac{mv^2}{r}+mg\\\Rightarrow N=\dfrac{2000\times 18^2}{24}+2000\times 9.81\\\Rightarrow N=46620\ \text{N}

The force exerted on the track is 46620\ \text{N}.

8 0
3 years ago
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