Answer:

Explanation:
It is given that,
Mass of the clock, m = 108 kg
Force acting on it when it is in motion, 
After the clock is in motion, a horizontal force of 521 N keeps it moving with a constant velocity, F' = 521 N
It is assumed to find the coefficient of between the clock and the floor. The force of friction is given by :




So, the coefficient of static friction between the clock and the floor is 0.6. Hence, this is the required solution.
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Answer:
V = (Vx^2 + Vy^2)^1/2 = (40^2 + 62^2)^1/2
V = 73.8 m/s
tan theta = Vy / Vx = 62/40 = 1.55
theta = 57.2 deg
Answer:
A) 2.89 × 105 N/C, radially inward
Explanation:
The magnitude of the electric field generated by a charged sphere is given by the following formula:
( 1 )
k: Coulomb's constant = 8.98*10^9 Nm^2/C^2
Q: charge of the sphere = -6.50*10^-6 C
r: distance from the center of the sphere to the point in which E is calculated
r = 0.150m + 0.300m = 0.450 m
You replace the values of Q and r in the equation (1):

The electric field points radially inward because the charge is negative.
hence, the answer is:
A) 2.89 × 105 N/C, radially inward
There are two main reasons why a bouncing ball rise to a lower height with each bounce: 1) because every time it hits the ground it encounters friction, which slows it down, and every time it rises from the ground it encounters air resistance.