When attempting to develop better decision making skills, communication with peers should be kept to a minimum. True or false

A uniform 1.6-kg rod that is 0.89 m long is suspended at rest from the ceiling by two springs, one at each end. Both springs han

artcher [175]

Answer:

8.27°

Explanation:

To angle difference will be determined by the difference in the displacement of the springs, produced by the weight of the center of mass of the rod.

$d=y_1-y_2=\frac{F_1}{k_1}-\frac{F_2}{k_2}=\frac{0.5mg}{31N/m}-\frac{0.5mg}{63N/m}\\\\d=0.5(1.6kg)(9.8m/s^2)[\frac{1}{31N/m}-\frac{1}{63N/m}]=0.128m$

by a simple trigonometric relation you obtain that the angle:

$sin\theta=\frac{d}{l}=\frac{0.128m}{0.89m}=0.144\\\\\theta=sin^{-1}(0.144)=8.27\°$

hence, the angle between the rod and the horizontal is 8.27°

4 0

2 years ago

What is the 4 digit code

Contact [7]

Answer:

lol doge meme

Explanation:

8 0

2 years ago

Do not have definite size and always take the shape of their contanier

sladkih [1.3K]

Answer:

water or h2o

Explanation:

7 0

3 years ago

The work function of a metal surface is 4.80 × 10-19 J. The maximum speed of the electrons emitted from the surface is vA = 7.7

poizon [28]

Answer:

$\lambda_A=2.65177\times 10^{-7}\ m$

$\lambda_B=3.32344\times 10^{-7}\ m$

Explanation:

h = Planck's constant = $6.63\times 10^{-34}\ m^2kg/s$

c = Speed of light = $3\times 10^8\ m/s$

m = Mass of electron = $9.11\times 10^{-31}\ kg$

$W_0$ = Work function = $4.8\times 10^{-19}\ J$

$v_A$ = Velocity of A particle = $7.7\times 10^5\ m/s$

$v_B$ = Velocity of B particle = $5.1\times 10^5\ m/s$

The wavelength is given by

$\lambda=\frac{hc}{\frac{1}{2}mv^2+W_0}$

$\lambda_A=\frac{6.63\times 10^{-34}\times 3\times 10^8}{\frac{1}{2}9.11\times 10^{-31}(7.7\times 10^5)^2+4.8\times 10^{-19}}\\\Rightarrow \lambda_A=2.65177\times 10^{-7}\ m$

The wavelength $\lambda_A=2.65177\times 10^{-7}\ m$

$\lambda_B=\frac{6.63\times 10^{-34}\times 3\times 10^8}{\frac{1}{2}9.11\times 10^{-31}(5.1\times 10^5)^2+4.8\times 10^{-19}}\\\Rightarrow \lambda_B=3.32344\times 10^{-7}\ m$

The wavelength $\lambda_B=3.32344\times 10^{-7}\ m$

5 0

3 years ago

An elephant of mass 2800kg has feet of average area of 200 cm2. A vulture of mass 12 kg walks beside the elephant on a muddy are

hoa [83]

Explanation:

The formula we are going to use is

Pressure = F/A

Elephant:

First, we need to convert weight into newtons.

1kg=9.8 newtons, so 2800kg × newtons = 27440newtons

For 4 feet= 200×4= 800cm^2

Convert the area to meter squared using the following:

1 centimeter squared = 0.0001 meters squared

800cm^2×0.0001= 0.08m^2

Pressure=F/A

Pressure= 27440/0.08

The pressure exerted on the ground by the elephant is 343000 Pascals.

Vulture:

12kg×9.8=117.6newtons

for 2 feet= 2.0×2=4cm^2

4×0.0001=0.0004m^2

117.6/0.0004= 294000 Pascals

To compare the pressure, just do a ratio of the elephant's pressure to vulture's pressure.

343000/294000≈ 1.17

So the pressure is about 1 times bigger.

Keep in mind that the elephant has 4 feet, which help to increase the area which in turn decrease the pressure.

7 0

3 years ago