Explanation:
It is given that,
Electric field strength, E = 20,000 N/C
Spacing between parallel-plate capacitor, d = 1 mm = 0.001 m
Initial velocity of electron, u = 0
Let v is the electron’s speed when it reaches the positive plate. The force acting on the electron is :
Also,
Using third equation of motion as :
v = 2649528.2599 m/s
or
So, the velocity of the electron when it reaches the positive plate is . Hence, this is the required solution.
Answer:
Magnitude of the force is 2601.9 N
Explanation:
m = 450 kg
coefficient of static friction μs = 0.73
coefficient of kinetic friction is μk = 0.59
The force required to start crate moving is .
but once crate starts moving the force of friction is reduced .
Hence to keep crate moving at constant velocity we have to reduce the force pushing crate ie .
Then the above pushing force will equal the frictional force due to kinetic friction and constant velocity is possible as forces are balanced.
Magnitude of the force