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Vikki [24]
4 years ago
10

A substance can be classified by its physical properties, which are properties that what?

Chemistry
1 answer:
DanielleElmas [232]4 years ago
7 0
Physical properties define the appearance of that substance. 
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What are 2 ways that convection currents in the oceans distribute the sun's energy?
dezoksy [38]

Answer:

When air in contact with the ocean is at a different temperature than the sea surface, heat transfer by conduction takes place. The ocean also absorbs and stores energy from the sun, and when precipitation falls, it releases heat energy into the atmosphere.

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For each pair, which has higher potential energy?
Allushta [10]

Answer:

Maybe A)

Explanation:

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4 years ago
Addition of 6 m hcl to which substance will not result in gas evolution?
saul85 [17]

There is no gaseous product when NaNO3 reacts with 6M HCl.

We must note that gas evolution is one of the signs that a chemical reaction has taken place. Hence, we must consider the options and look out for an option in which reaction with HCl does not lead to a gaseous product. This is the option that does not lead to evolution of a gas.

Let us consider the reaction; NaNO3(s) + HCl(aq) ---> NaCl(s) + HNO3(aq), there is no gaseous product hence NaNO3 does not result in gas evolution upon addition of 6M HCl.

Missing parts;

Addition of 6 M HCl to which substance will NOT result in gas evolution?

(A) Al

(B) Zn

(C) K2CO3

(D) NaNO3

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6 0
3 years ago
Which of the following would double the pressure on a contained gas at constant temperature? A. doubling the volume of the conta
lesantik [10]
A. Doubling the volume of the container
3 0
4 years ago
A sample of CH4 is confined in a water manometer. The temperature of the system is 30.0 °C and the atmospheric pressure is 98.70
kakasveta [241]

Explanation:

The given data is as follows.

  P_{atm} = 98.70 kPa = 98700 Pa,  

      T = 30^{o}C = (30 + 273) K = 303 K

      height (h) = 30 mm = 0.03 m (as 1 m = 100 mm)

Density = 13.534 g/mL = 13.534 g/mL \times \frac{10^{6}cm^{3}}{1 m^{3}} \times \frac{1 kg}{1000 g}

                = 13534 kg/m^{3}

The relation between pressure and atmospheric pressure is as follows.

             P = P_{atm} + \rho gh

Putting the given values into the above formula as follows.

            P = P_{atm} + \rho gh

               = 98700 Pa + 13534 \times 9.81 \times 0.03 m

               = 102683.05 Pa

               = 102.68 kPa

thus, we can conclude that the pressure of the given methane gas is 102.68 kPa.

8 0
4 years ago
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