Answer:Noble gases:
are highly reactive.
react only with other gases.
do not appear in the periodic table.
are not very reactive with other elements.
Explanation:Noble gases:
are highly reactive.
react only with other gases.
do not appear in the periodic table.
are not very reactive with other elements.
The required mole ratio of NH₃ to N₂ in the given chemical reaction is 2:4.
<h3>What is the stoichiometry?</h3>
Stoichiometry of the reaction gives idea about the number of entities present on the reaction before and after the reaction.
Given chemical reaction is:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
From the stoichiometry of the reaction it is clear that:
4 moles of NH₃ = produces 2 moles of N₂
Mole ratio NH₃ to N₂ is 2:4.
Hence required mole ratio is 2:4.
To know more about mole ratio, visit the below link:
brainly.com/question/504601
How am I supposed to help you if there's not picture of what the problem is
Answer:
A population or community research line can be carried out, wherever at a certain point in time, regardless of whether it is a cross-sectional study.
In addition, the people who would be the population to be studied or the object of study might or might not know the cause of the study (blind) while the researcher could be experimentally participatory.
Explanation:
They are prevalence studies, in which the presence of a health condition or state is determined in a well-defined population and in a determined time frame: one day, one week, a particular moment in life, even if it does not temporarily coincide in all the subjects (for example, the blood pressure figures at the time of entering the school or at the beginning of the holidays, the prevalence of diabetes in hospitalized patients on a given day, etc.).
They are like "photographs" of a state of affairs at a given moment. The simultaneous determination of what is understood by exposure and event does not allow defining causality.
http://www.atnf.csiro.au/outreach/education/senior/cosmicengine/stars_hrdiagram.html. This will give u the answer, just go to link
