Answer:
(a) W = 645 J
(b) E= 461.9 J
(c) The work done by the normal force = 0 J as no displacement is taking place in that direction
(d)The work done by the gravitational force 0 J, as there is zero displacement in that direction too.
(e) ΔKE= 183 J
(f) v = 3.16 m/s
Explanation:
A 36.5 kg box initially at rest is pushed 4.3 m along a rough, horizontal floor with a constant applied horizontal force of 150 N. If the coefficient of friction between box and floor is 0.300, find the following.
(a) the work done by the applied force
W=F*d
W=150*4.3
W = 645 J
(b)
The increase in internal energy in the box-floor system due to friction
E=0.300*36.5*9.81*4.30
E= 461.9 J
(c)
The work done by the normal force = 0 J as no displacement is taking place in that direction
(d)
The work done by the gravitational force 0 J, as there is zero displacement in that direction too.
(e)
the change in kinetic energy of the box
ΔKE=645 - 461.9 J
ΔKE= 183 J
(f)
The final speed of the box
0.5*36.5*v^2 = 183 J
v^2 = 10
v = 3.16 m/s