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4 years ago

15

Which of the following did Malthus fail to take into consideration?

2 answers:

attashe74 [19]4 years ago

8 0

Explanation:

Malthus said that "population would grow at a geometric rate while food production increased at an arithmetic rate. Unless birth rates were checked or wars and disease raised the death rate, he said, England and the rest of world would face inevitable famine and a subsistence standard of living."

Malthus didn't take in cosideration that many technological advances (such as machines, preservatives, refrigeration, pesticides) would help to produce huge quantities of food to equilibrate that population grow.

saveliy_v [14]4 years ago

4 0

Answer: humans would find more efficient ways of growing crops

Explanation:

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4 years ago

The total mass of the atmosphere is about 5.00 x 1018 kg. How many moles each of air, O2, and CO2 are present in the atmosphere?

n200080 [17]

<u>Answer:</u> The moles of oxygen and carbon dioxide in air is $3.63\times 10^{19}mol$ and $7.18\times 10^{16}mol$ respectively

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of atmosphere = $5.00\times 10^{18}kg=5.00\times 10^{21}g$

Average molar mass of atmosphere = 28.96 g/mol

Putting values in above equation, we get:

$\text{Moles of atmosphere}=\frac{5.00\times 10^{21}g}{28.96g/mol}=1.73\times 10^{20}mol$

We know that:

Percent of oxygen in air = 21 %

Percent of carbon dioxide in air = 0.0415 %

Moles of oxygen in air = $\frac{21}{100}\times 1.73\times 10^{20}=3.63\times 10^{19}mol$

Moles of carbon dioxide in air = $\frac{0.0415}{100}\times 1.73\times 10^{20}=7.18\times 10^{16}mol$

Hence, the moles of oxygen and carbon dioxide in air is $3.63\times 10^{19}mol$ and $7.18\times 10^{16}mol$ respectively

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3 years ago