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3 years ago

Which of the following did Malthus fail to take into consideration?

Chemistry

2 answers:

attashe74 [19]3 years ago

8 0

Explanation:

Malthus said that "population would grow at a geometric rate while food production increased at an arithmetic rate. Unless birth rates were checked or wars and disease raised the death rate, he said, England and the rest of world would face inevitable famine and a subsistence standard of living."

Malthus didn't take in cosideration that many technological advances (such as machines, preservatives, refrigeration, pesticides) would help to produce huge quantities of food to equilibrate that population grow.

saveliy_v [14]3 years ago

4 0

Answer: humans would find more efficient ways of growing crops

Explanation:

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N2O5 decomposes to form NO2 and O2 with first-order kinetics. The initial concentration of N2O5 is 3.0 M and the reaction runs f

kow [346]

Answer : The final concentration of $N_2O_5$ is, 2.9 M

Explanation :

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $5.89\times 10^{-3}\text{ min}^{-1}$

t = time passed by the sample = 3.5 min

a = initial concentration of the reactant = 3.0 M

a - x = concentration left after decay process = ?

Now put all the given values in above equation, we get

$3.5=\frac{2.303}{5.89\times 10^{-3}}\log\frac{3.0}{a-x}$

$a-x=2.9M$

Thus, the final concentration of $N_2O_5$ is, 2.9 M

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xxTIMURxx [149]

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What is the correct electron configuration for oxygen?

s344n2d4d5 [400]

It would be: 1s2, 2s2, 2p4

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An ionic bond involves two elements...

valina [46]

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Explanation:

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Determine how many atoms of pure silver will be created when 19.83 x 1023 atoms of copper are used in the following reaction:

Lubov Fominskaja [6]

Answer:

$\boxed{3.966 \times 10^{24}\text{ atoms of Ag}}$

Explanation:

(a) Balanced equation

Cu + 2AgNO₃ ⟶ Cu(NO₃)₂+ 2Ag

(b) Calculation

You want to convert atoms of Cu to atoms of Ag.

The atomic ratio is ratio is 2 atoms Ag:1 atom Cu

$\text{Atoms of Ag} = 19.83 \times 10^{23}\text{atoms Cu} \times \dfrac{\text{2 atoms Ag}}{\text{1 atom Cu}}\\\\= 3.966 \times 10^{24}\text{ atoms of Ag}\\\\\text{The reaction will produce }\boxed{\mathbf{3.966 \times 10^{24}}\textbf{ atoms of Ag}}$

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3 years ago

Read 2 more answers