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3 years ago

5

An ant is crawling along a straight wire, which we shall call the x axis, from A to B to C to D

1 answer:

Inga [223]3 years ago

5 0

A high quality insecticide applied all along the axis and the surrounding area can protect against a recurrence for a substantial period of time.

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6th grade science If you answer this your the brainiest

motikmotik

Answer:

8. sketches and models helped the astronauts in their training program as they prepare for their missions

9. before building the Mars lander , students need to sketch their design

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3 years ago

A cube has a density of 1900 kg/m 3 kg/m3 while at rest in the laboratory. What is the cube's density as measured by an experime

Deffense [45]

Answer:

4847.94844926 kg/m³

Explanation:

$\rho'$ = Actual density of cube = 1900 kg/m³

$\rho$ = Density change due to motion

v = Velocity of cube = 0.92c

c = Speed of light = $3\times 10^8\ m/s$

Relativistic density is given by

$\rho=\dfrac{\rho'}{\sqrt{1-\dfrac{v^2}{c^2}}}\\\Rightarrow \rho=\dfrac{1900}{\sqrt{1-\dfrac{0.92^2c^2}{c^2}}}\\\Rightarrow \rho=\dfrac{1900}{\sqrt{1-0.92^2}}\\\Rightarrow \rho=4847.94844926\ kg/m^3$

The cube's density as measured by an experimenter in the laboratory is 4847.94844926 kg/m³

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3 years ago

In any homogeneous medium, the constant factor is a wave's:

eimsori [14]

answer is frequency

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3 years ago

Read 2 more answers

The gravitational force between two objects with masses, m1 and m2, separated by a distance "r" is given by F = (Gm1m2)/ r2, whe

diamong [38]

Answer:

it increases

Explanation:

4 0

3 years ago

A student is experimenting with some insulated copper wire and a power supply. She winds a single layer of the wire on a tube wi

OverLord2011 [107]

Answer:

$P=214.7187\,W$

Explanation:

Given that:

Diameter of the solenoid, $D=10\,cm=0.1\,m$

length of the solenoid, $L=90\,cm=0.9\,m$

diameter of the wire, $d=0.1\,cm=10^{-3}\,m$

magnetic field at the center of the solenoid, $B=7.4\times 10^{-3}\,T$

<u>Now we need the no. of turns incorporated in the length of 90 cm:</u>

$N=\frac{Length\,\,of\,\,solenoid}{diameter\,\,of\,\, wire}$

$N=\frac{L}{d}$

$N=\frac{0.9}{10^{-3}}$

$N=900\,\,turns$

For solenoids we have:

$B=\mu.n.I$ ...............................(1)

where:

$\mu=$ permeability of the medium

n = no. of turns per unit length

I = current in the coil

So,

$n=\frac{900}{0.9}$

$n=1000\,turns\,.\,m^{-1}$

Now putting the respective values in the eq. (1)

$7.4\times 10^{-3}=4\pi\times10^{-7}\times 1000\times I$

$I=5.8887\,A$

For copper we have resistivity:

$\rho=1.72\times 10^{-8}\, \Omega.m$

We know that resistance is given by:

$R=\rho.\frac{l}{a}$ .....................................(2)

where:

l = length of the conducting wire

a = cross sectional area of the conducting wire

<u>Now we need the length (l) of the wire:</u>

Circumference of the solenoid,

$C=\pi.D$

$C=0.1\pi\,m$

$\therefore l=C\times N$

$l=90\pi\,m$

&

<u>Cross-sectional area of wire:</u>

$a=\pi.\frac{d^2}{4}$

$a=\pi. \frac{(10^{-3})^2}{4}\,m^2$

<u>Resistance from eq. (2):</u>

$R=1.72\times 10^{-8}\times \frac{90\pi}{\pi. \frac{(10^{-3})^2}{4}}$

$R=6.192 \,\Omega$

For power we have:

$P=I^2.R$

$P=5.8887^2 \times 6.192$

$P=214.7187\,W$

6 0

3 years ago