An electron and a proton have the same kinetic energy and are moving at speeds much less than the speed of light. Determine the
ratio of the de Broglie wavelength of the electron to that of the proton.
1 answer:
Answer:
The ratio of the Broglie wavelength of an electron to that of the proton is 42.85.
Explanation:
let λe be the Broglie wavelength of the electron and λp be the Broglie wavelength of the proton, Me be the mass of the electron and Mp be the mass of the proton. let h be the Planck constant, Kep be the kinetic energy of the proton and KEe be the kinetic energy of the electron
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Answer:
a) = 4.67m/s
b) V = 8.29 m/s
Explanation:
Givens:
The bullet is 5.30g moving at 963m/s and its speed reduced to 426m/s. The wooden block is 610g.
a) From conservation of linear momentum
Pi = Pf
where are the mass and the initial velocity of the bullet,
and
are the mass and the initial velocity of the wooden block, and
and
are the final velocities of the wooden block and the bullet
The wooden block is initial at rest this yields
By solving for adn substitute the givens
=
=
= 4.67m/s
b) The center of mass speed is defined as
substituting:
V = 8.29 m/s