An electron and a proton have the same kinetic energy and are moving at speeds much less than the speed of light. Determine the
ratio of the de Broglie wavelength of the electron to that of the proton.
1 answer:
Answer:
The ratio of the Broglie wavelength of an electron to that of the proton is 42.85.
Explanation:
let λe be the Broglie wavelength of the electron and λp be the Broglie wavelength of the proton, Me be the mass of the electron and Mp be the mass of the proton. let h be the Planck constant, Kep be the kinetic energy of the proton and KEe be the kinetic energy of the electron
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Answer:
Explanation:
<u><em>Finding the net force:</em></u>
<u><em>Firstly , we'll find force of Friction:</em></u>
Where is the coefficient of friction and m = 13.6 kg
<u><em>Now, Finding the net force:</em></u>
<u><em>Finding Acceleration:</em></u>
(a) 29.8 m/s
To solve this problem, we start by analyze the vertical motion first. This is a free fall motion, so we can use the following suvat equation:
where, taking upward as positive direction:
is the final vertical velocity
is the initial vertical velocity (zero because the pebble is launched horizontally)
is the acceleration of gravity
s = -25.0 m is the displacement
Solving for vy,
(downward, so we take the negative solution)
The pebble also have a horizontal component of the velocity, which remains constant during the whole motion, so it is
So, the final speed of the pebble as it strikes the ground is
(b) 29.8 m/s
In this case, the pebble is launched straight up, so its initial vertical velocity is
So we can find the final vertical velocity using the same suvat equation as before:
(downward, so we take the negative solution)
The horizontal speed instead is zero, since the pebble is initially launched vertically, so the final speed is just equal to the magnitude of the vertical velocity:
v = 29.8 m/s
(c) 29.8 m/s
This case is similarly to the previous one: the only difference here is that the pebble is launched straight down instead than up, therefore
Using again the same suvat equation:
(downward, so we take the negative solution)
As before, the horizontal speed instead is zero, since the pebble is initially launched vertically, so the final speed is just equal to the magnitude of the vertical velocity:
v = 29.8 m/s
We notice that the final value of the speed is always the same in all the three parts, so it does not depend on the direction of launching. This is due to the law of conservation of energy: in fact, the initial mechanical energy of the pebble (kinetic+potential) is the same in all three cases (because the height h does not change, and the speed v does not change either), and the kinetic energy gained during the fall is also the same (since the pebble falls the same distance in all 3 cases), therefore the final speed must also be the same.
Answer:
21 m
Explanation:
The motion of the frog is a uniform motion (constant speed), therefore we can find the distance travelled by using
where
d is the distance covered
v is the speed
t is the time
The frog in this problem has a speed of
v = 2.1 m/s
and therefore, after t = 10 s, the distance it covered is