Answer:
8.2N
Explanation:
I took the test and got it right :)
One with greater mass (8kg)
Answer:
X=m*g/K
Explanation:
Since the elastic force of the spring is balancing the force of gravity:
Fe = m*g
Now, on the spring by Hook's law, the magnitude of the elastic force will be:
Fe = K*X where K is the elastic constant of the spring and X is the distance the spring is strectches measured from its original lenght to its current length.
Replacing this value:
K*X = m*g Solving for X:
X = m*g/K This value is directly proportional to the object's weight and inversely proportional to the spring's constant.
Answer:
132 N
Explanation:
Given that a 1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in the opposite direction. If the hammer is in contact with the nail for 0.025 s, what is the magnitude of the average force exerted by the hammer on the nail
From Newton 2nd law of motion,
Change in momentum = impulse.
Change in momentum = m( V - U )
Substitute all the parameters into the formula
Change in momentum = 1.1 ( 4.5 - 1.5 )
Change in momentum = 1.1 × 3
Change in momentum = 3.3 kgm/s
Impulse = Ft
That is,
Ft = 3.3
Substitute time t into the formula above
F × 0.025 = 3.3
F = 3.3 / 0.025
F = 132 N
Therefore, the magnitude of the average force exerted by the hammer on the nail is 132 N.
If a photon has a wavelength of about 10^-10 meters, it would be certainly in the X rays region and it would have a frequency of 2.99792458x10^18 Hz, that you can easily calculate using the relation that states that the product of the wavelength and the frequency of an electromagnetic wave aka light is always equal to 299,792,458 m/s which is the exact value of the speed of light!
