given that acceleration due to gravity is a = -10 m/s^2
initial speed will be ZERO
and we need to find the displacement in t = 8 s
now we can use kinematics equation to find the displacement
![\delta y = v_y * t + \frac{1}{2}at^2](https://tex.z-dn.net/?f=%5Cdelta%20y%20%3D%20v_y%20%2A%20t%20%2B%20%5Cfrac%7B1%7D%7B2%7Dat%5E2)
now plug in all values in it
![\delta y = 0* 8 + \frac{1}{2}*(-10)*8^2](https://tex.z-dn.net/?f=%5Cdelta%20y%20%3D%200%2A%208%20%2B%20%5Cfrac%7B1%7D%7B2%7D%2A%28-10%29%2A8%5E2)
![\delta y = -320 m](https://tex.z-dn.net/?f=%5Cdelta%20y%20%3D%20-320%20m)
<em>so it will displace downwards by 320 m</em>
Answer:
a) the spring will stretch 60.19 mm
with the same box attached as it accelerates upwards
b) spring will be relaxed when the elevator accelerates downwards at 9.81 m/s²
Explanation:
Given that;
Gravitational acceleration g = 9.81 m/s²
Mass m = 5 kg
Extension of the spring X = 50 mm = 0.05 m
Spring constant k = ?
we know that;
mg = kX
5 × 9.81 = k(0.05)
k = 981 N/m
a)
Given that; Acceleration of the elevator a = 2 m/s² upwards
Extension of the spring in this situation = X1
Force exerted by the spring = F
we know that;
ma = F - mg
ma = kX1 - mg
we substitute
5 × 2 = 981 × X1 - (5 ×9.81 )
X1 = 0.06019 m
X1 = 60.19 mm
Therefore the spring will stretch 60.19 mm
with the same box attached as it accelerates upwards
B)
Acceleration of the elevator = a
The spring is relaxed i.e, it is not exerting any force on the box.
Only the weight force of the box is exerted on the box.
ma = mg
a = g
a = 9.81 m/s² downwards.
Therefore spring will be relaxed when the elevator accelerates downwards at 9.81 m/s²
weathering refers to the actual breaking part of the rock or soil. deposition happens when the weathered and eroded material is deposited and finally comes to a stand still.
People have many different theories but ancient Ramp Find Deepens Mystery. “Using a sled which carried a stone block and was attached with ropes to these wooden posts, ancient Egyptians were able to pull up the alabaster blocks out of the quarry on very steep slopes of 20 percent or more.”