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jonny [76]
3 years ago
12

What compounds break up into ions solution? ​

Chemistry
2 answers:
Korolek [52]3 years ago
5 0

Answer:

Acids are compounds that dissociate (break) into hydrogen (H+) ions and another compound when placed in an aqueous solution.

Explanation:

Savatey [412]3 years ago
5 0

Acid and base  compounds break up into ions solution.

<h3><u> Explanation:</u></h3>

Acids are the compounds that breaks into hydrogen ions. Bases are those compounds that dissociate into hydroxide or OH - ions. When you put an ionic or electrovalent compound into water , then it breaks apart into two ions.If one of them is H+ ions, then the solution is known to be acidic.

A good  example of strong acid is hydrogen chloride which breaks into water and releases ions. If we take the example of bases than if one of the releasing ion is OH- in the solution than the solution is basic . A good example of this is sodium hydroxide (NaOH).

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I need to find the chemical equation
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Answer:

2NaCN + CaCO3 --> Na2CO3 + Ca(CN)2

Explanation:

Knowing the names gets us: NaCN + CaCO3 --> Na2CO3 + Ca(CN)2

Balance: there are two sodiums and cyanides on the product side so add a 2 to the reactant side.

4 0
3 years ago
Which statement describes both homogeneous mixtures and heterogeneous mixtures?
stiks02 [169]

Answer:

both are the types of mixture and both are impure substances that donot have fixed composition and the composition of constituents  is not uniform

5 0
2 years ago
Forests are the only carbon sinks on Earth. Please select the best answer from the choices provided T F
dmitriy555 [2]
False, as oceans can act as carbon sinks along with forests. 
4 0
3 years ago
Read 2 more answers
What are valence electrons ?
Arada [10]

Answer:In chemistry, a valence electron is an outer shell electron that is associated with an atom, and that can participate in the formation of a chemical bond if the outer shell is not closed; in a single covalent bond, both atoms in the bond contribute one valence electron in order to form a shared pair.

Explanation: hope this helped

8 0
2 years ago
Equal molar quantities of Ca2 and EDTA (H4Y) are added to make a 0.010 M solution of CaY2- at pH 10. The formation constant for
abruzzese [7]

Answer:

the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷

Explanation:

Given the data in the question;

Ca^{2+ + y^{4- ⇄  CaY^{2-

Formation constant Kf

Kf = CaY^{2- / ( [Ca^{2+][y^{4-] ) = 5.0 × 10¹⁰

Now,

[y^{4-] = \alpha _4CH_4Y; ∝₄ = 0.35

so the equilibrium is;

Ca^{2+ + H_4Y ⇄  CaY^{2- + 4H⁺

Given that; CH_4Y = Ca^{2+     { 1 mol Ca^{2+  reacts with 1 mol H_4Y  }

so at equilibrium, CH_4Y = Ca^{2+ = x

∴

Ca^{2+ + y^{4- ⇄  CaY^{2-

x        + x         0.010-x

since Kf is high, them x will be small so, 0.010-x is approximately 0.010

so;

Kf = CaY^{2- / ( [Ca^{2+][y^{4-] ) =  CaY^{2- / ( [Ca^{2+][\alpha _4CH_4Y] )  = 5.0 × 10¹⁰

⇒ CaY^{2- / ( [Ca^{2+][\alpha _4CH_4Y] )  = 5.0 × 10¹⁰

⇒ 0.010 / ( [x][ 0.35 × x] )  = 5.0 × 10¹⁰

⇒ 0.010 / 0.35x²  = 5.0 × 10¹⁰

⇒ x² = 0.010 / ( 0.35 × 5.0 × 10¹⁰ )

⇒ x² = 0.010 / 1.75 × 10¹⁰

⇒ x² = 0.010 / 1.75 × 10¹⁰

⇒ x² = 5.7142857 × 10⁻¹³

⇒ x = √(5.7142857 × 10⁻¹³)

⇒ x = 7.559 × 10⁻⁷

Therefore, the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷

8 0
2 years ago
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