Which substance is the reducing agent in this reaction? 16h++2cr2o72−+c2h5oh→4cr3++11h2o+2co2 express your answer as a chemical formula?
1 answer:
16 H + + 2Cr2O72- + C2H5OH → 4 Cr3 + +11H2O +2CO2
The reducing agent is C2H5OH
Explanation
reducing agent is a substance that loses or donate electrons in a chemical reaction. C2H5OH is the one which donate electrons in the above chemical equation.
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