If the mass of a body is 9.8kg on the earth, what would be its mass on the moon?

John is a field researcher who studies social interaction within motorcycle groups. He is not an accomplished rider himself, but

uysha [10]

His role as a field research is that of a: Complete participant!
(Option D.)

~Good luck!

7 0

3 years ago

The mass of a particular eagle is twice that of a hunted pigeon. Suppose the pigeon is flying north at ????????,2=17.9vi,2=17.9

AleksAgata [21]

Answer:

V=27.24 m/s

Explanation:

We need to apply the linear momentum conservation theorem:

$m_1*v_{o1}+m_2*v_{o2}=m_t*v_{f}\\$

The velocity of the eagle its defined by its two components:

$v_x=V*cos(\theta)\\v_y=V*sin(\theta)\\v_x=35.9*cos(61.9^o)=16.9m/s\\v_y=35.9*sin(61.9^o)=31.7m/s$

$2*(16.9m/s(i)+31.66m/s(j))+17.9m/s(i)=3*v_f\\v_f=17.23m/s(i)+21.10m/s(j)$

because speed is a scalar value:

$V=\sqrt{(21.10m/s)^2+(17.23)^2}\\V=27.24m/s$

6 0

3 years ago

The hot glowing surfaces of stars emit energy in the form of electromagnetic radiation. It is a good approximation to assume e =

Svetllana [295]

Answer:

Explanation:

(a) Rigel, 2.7x10^32W, T = 11,000K

But L = 4pR²sT⁴

L = 2.7x10^32W, T = 11,000K, s= 5.67 x 10^-8, R= radius in meters

Rigel parallax, p = 0.00378 arc sec

Substituting the various values and making R the subject of the formula

R² = L/(4psT⁴)

R² = 2.7x10^32/(4 x 0.003878 x 5.67x10^-8 x (11,000)⁴)

R² = 2.7x10^32/1.2877x10^7

R² = 2.096761668 x 10^25

R = 4.579041021 x 10^12meters

(b)

Procyon B, 2.1x10^23W, T = 10,000K

But L = 4pR²sT⁴

L = 2.1x10^23W, T = 10,000K, s= 5.67 x 10^-8, R= radius in meters

Procyon B parallax, p = 0.00284 arc sec

R² = 2.1x10^23/(4 x 0.00284 x 5.67x10^-8 x (10,000)⁴)

R² = 2.1x10^23/(6.441 x 10^6)

R² = 3.26036 x 10^16

R = 1.80565 x 10^8 meters

(c) The radius of Rigel is given as 4.579041021 x 10^12meters and the radius of Procyon B is given by 1.80565 x 10^8 meters shows the remarkable difference between a super-giant star(Rigel) and a white dwarf star (Procyon B)

The radius of the sun a red star is 6.96 x 10^8meters which shows a certain level of resemblance with the size of a dwarf white star Procyon B.

The sun is larger than Procyon B as estimated above.

7 0

3 years ago

A certain gasoline engine has an efficiency of 35.3%. What would the hot reservoir temperature be for a Carnot engine having tha

levacccp [35]

Answer:

The temperature of hot reservoir is 669.24 K.

Explanation:

It is given that,

Efficiency of gasoline engine, $\eta=35.3\%=0.353$

Temperature of cold reservoir, $T_C=160^{\circ}C=433\ K$

We need to find the temperature of hot reservoir. The efficiency of Carnot engine is given by :

$\eta=1-\dfrac{T_C}{T_H}$

$T_H=\dfrac{T_C}{1-\eta}$

$T_H=\dfrac{433}{1-0.353}$

$T_H=669.24\ K$

So, the temperature of hot reservoir is 669.24 K. Hence, this is the required solution.

4 0

3 years ago

Find the power going through each circuit: Then, arrange the circuits from LOWEST power to HIGHEST power.

Lelechka [254]

Answer:

A. 9 Watts

B. 2.25 Watts

C. 4.5 Watts

Arranging the circuit from lowest power to highest power we have

Circuit B, circuit C, circuit A.

Explanation:

The power in an electric circuit can be obtained by the following equation:

Power (P) = current (I) x voltage (V)

P = IV

With the above equation, let us calculate the power of each circuit. This is illustrated below:

A. Current (I) = 3A

Voltage (V) = 3V

Power (P) =?

P = IV

P = 3 x 3 = 9watts

B. Current (I) = 1.5A

Voltage (V) = 1.5V

Power (P) =?

P = IV

P = 1.5 x 1.5 = 2.25watts

C. Current (I) = 1.5A

Voltage (V) = 3V

Power (P) =?

P = IV

P = 1.5 x 3 = 4.5watts

Arranging the circuit from lowest power to highest power we have

Circuit B, circuit C, circuit A.

3 0

3 years ago

If the mass of a body is 9.8kg on the earth, what would be its mass on the moon?​

If the mass of a body is 9.8kg on the earth, what would be its mass on the moon?