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3 years ago

Which compound dissolves in water to form an aqueous solution that can conduct an electric current?

1 answer:

4 0

The answer is (3) CH3COOH. CH3COOH is a acid. It can ionized in water. So the solution can conduct an electric current. And the other three can not be ionized in water.

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II. The student then takes a 1.00 M stock

-BARSIC- [3]

Answer:

0.244 M.

Explanation:

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 1 M

Volume of stock solution (V₁) = 0.305 L

Volume of diluted solution (V₂) = 1.25 L

Molarity of diluted solution (M₂) =?

The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:

M₁V₁ = M₂V₂

1 × 0.305 = M₂ × 1.25

0.305 = M₂ × 1.25

Divide both side by 1.25

M₂ = 0.305 / 1.25

M₂ = 0.244 M

Thus, the molarity of the diluted solution is 0.244 M

3 0

3 years ago

Calculate the freezing point of a solution 1.25 g benzene (C6H6) in 125 g of chloroform (CHCl3).

posledela

Answer:

The freezing point for the solution is -64.09°C

Explanation:

This problem can be solved, by the freezing point depression. This colligative problem shows, that the freezing point of a solution is lower than the freezing point of pure solvent.

ΔT = Kf. m

ΔT = T° freezing pure solvent - T° freezing solution

Kf = Cryscopic constant, for chloroform is 4.68

T°freezing pure solvent = -63.5°C

m is mol/kg of solvent → molality

Let's determine the moles of benzene

1.25 g / 78 g/mol = 0.0160 mol

Let's convert the mass of solvent to kg

125 g . 1kg / 1000 g = 0.125 kg

m = 0.0160 mol / 0.125 kg → 0.128 m

Let's go to the formula to replace the data

-63.5°C - T° freezing solution = 4.68 °C/m . 0.128 m

T° freezing solution = - (4.68 °C/m . 0.128 m + 63.5°C)

T° freezing solution = - 64.09°C

3 0

3 years ago

Can somebody answer this please

Murrr4er [49]

The answer should be A.

7 0

3 years ago

What is the meaning of the word organism

Lady_Fox [76]

Answer:

B) any complex thing with properties normally associated with living things

5 0

3 years ago

Read 2 more answers

Using the Bohr model, determine the energy in joules of the photon produced when an electron in a Li2+ ion moves from the orbit

djverab [1.8K]

Answer:

1.64x10⁻¹⁸ J

Explanation:

By the Bohr model, the electrons surround the nucleus of the atom in shells or levels of energy. Each one has it's energy, and the electron doesn't fall to the nucleus because it can reach another level of energy, and then return to its level.

When the electrons go to another level, it absorbs energy, and then, when return, this energy is released, as a photon (generally as luminous energy). The value of the energy can be calculated by:

E = hc/λ

Where h is the Planck constant (6.626x10⁻³⁴ J.s), c is the light speed (3.00x10⁸ m/s), and λ is the wavelength of the photon.

The wavelength can be calculated by:

1/λ = R*(1/nf² - 1/ni²)

Where R is the Rydberg constant (1.097x10⁷ m⁻¹), nf is the final orbit, and ni the initial orbit. So:

1/λ = 1.097x10⁷ *(1/1² - 1/2²)

1/λ = 8.227x10⁶

λ = 1.215x10⁻⁷ m

So, the energy is:

E = (6.626x10⁻³⁴ * 3.00x10⁸)/(1.215x10⁻⁷)

E = 1.64x10⁻¹⁸ J

3 0

3 years ago