20 Ca :
1s², 2s², 2p⁶, 3s², 3p⁶, 4s²<span>
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Answer D
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Answer:
D. N₂O
Explanation:
Let's assume we have 100 g of the compound. That means it consists of 63.61 grams of nitrogen and 36.69 grams of oxygen.
Converting masses to moles:
63.61 g N × (1 mol N / 14.01 g N) = 4.540 mol N
36.69 g O × (1 mol O / 16.00 g O) = 2.293 mol O
Normalize by dividing by the smallest:
4.540 / 2.293 = 1.980 mol N
2.293 / 2.293 = 1.000 mol O
So there is approximately twice as many N atoms as O atoms. The empirical formula is therefore N₂O.
Answer:
v = 46.5 m/s
Explanation:
Given data:
Mass of car = 1210 kg
Momentum of car = 56250 kg m/s
Velocity of car = ?
Solution:
Formula:
p = mv
p = momentum
m = mass
v = velocity
Now we will put values in formula:
56250 kg m/s = 1210 kg × v
v = 56250 kg m/s / 1210 kg
v = 46.5 m/s
So a car having mass of 1210 kg with momentum 56250 kg m/s having 46.5 m/s velocity.
Answer:
1. 9.57 × 10^-9 moles.
2. 7.38mol
Explanation:
1.) To find the number of moles there are in the number of particles in an atom, we divide the number of particles (nA) by Avagadro's constant (6.02 × 10^23)
Hence, to find the number of moles (n) of Manganese (Mn), we say:
5.76 x 10^15 atoms ÷ 6.02 × 10^23
5.76/6.02 × 10^(15-23)
= 0.957 × 10^-8
= 9.57 × 10^-9 moles.
2.) Mole = mass/molar mass
Molar mass of sodium chloride (NaCl) = 23 + 35.5
= 58.5g/mol
mole = 431.6 g ÷ 58.5g/mol
mole = 7.38mol
Density depends on both the mass and the volume of an object. If you cut a bar of gold in half, you would have two bars with half the mass of the original bar. However, each bar would also have half the volume of the original bar. The density of gold does not change.
