ANSWERS:

Explanation:
Given:
Piston cylinder assembly which mean that the process is constant pressure process P=C.
<u>AMMONIA </u>
state(1)
saturated vapor 
The temperature 
Isothermal process 
a)
( double)
b)
(reduced by half)
To find the final state by giving the quality in lbf/in we assume the friction is neglected and the system is in equilibrium.
state(1)
using PVT data for saturated ammonia

then the state exists in the supper heated region.
a) from standard data



assume linear interpolation


b)

from standard data

then the state exist in the wet zone


Answer:
0.5 kW
Explanation:
The given parameters are;
Volume of tank = 1 m³
Pressure of air entering tank = 1 bar
Temperature of air = 27°C = 300.15 K
Temperature after heating = 477 °C = 750.15 K
V₂ = 1 m³
P₁V₁/T₁ = P₂V₂/T₂
P₁ = P₂
V₁ = T₁×V₂/T₂ = 300.15 * 1 /750.15 = 0.4 m³

For ideal gas,
= 5/2×R = 5/2*0.287 = 0.7175 kJ
PV = NKT
N = PV/(KT) = 100000×1/(750.15×1.38×10⁻²³)
N = 9.66×10²⁴
Number of moles of air = 9.66×10²⁴/(6.02×10²³) = 16.05 moles
The average mass of one mole of air = 28.8 g
Therefore, the total mass = 28.8*16.05 = 462.135 g = 0.46 kg
∴ dQ = 0.46*0.7175*(750.15 - 300.15) = 149.211 kJ
The power input required = The rate of heat transfer = 149.211/(60*5)
The power input required = 0.49737 kW ≈ 0.5 kW.
Answer:
Maximum number of vehicle = 308
Explanation:
See the attached file for the calculation.
Answer:

Explanation:
The stress experimented by the circular bar is:
![\sigma = \left[\frac{2000\, lbf}{\frac{\pi}{4}\cdot (0.5\,in)^{2}}\right]\cdot \left(\frac{1\,kpsi}{1000\,psi} \right)](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cleft%5B%5Cfrac%7B2000%5C%2C%20lbf%7D%7B%5Cfrac%7B%5Cpi%7D%7B4%7D%5Ccdot%20%280.5%5C%2Cin%29%5E%7B2%7D%7D%5Cright%5D%5Ccdot%20%5Cleft%28%5Cfrac%7B1%5C%2Ckpsi%7D%7B1000%5C%2Cpsi%7D%20%5Cright%29)

The safety factor is:

