Answer:
Z = 3 + 0.23t
The water level is rising
Explanation:
Please see attachment for the equation
A car air-conditioning unit has a 0.5-kg aluminum storage cylinder that is sealed with a valve, and itcontains 2 L of refrigeran
1 answer:
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Answer:
Final mass of Argon= 2.46 kg
Explanation:
Initial mass of Argon gas ( M1 ) = 4 kg
P1 = 450 kPa
T1 = 30°C = 303 K
P2 = 200 kPa
k ( specific heat ratio of Argon ) = 1.667
assuming a reversible adiabatic process
<u>Calculate the value of the M2 </u>
Applying ideal gas equation ( PV = mRT )
P₁V / P₂V = m₁ RT₁ / m₂ RT₂
hence : m2 = P₂T₁ / P₁T₂ * m₁
= (200 * 303 ) / (450 * 219 ) * 4
= 2.46 kg
<em>Note: Calculation for T2 is attached below</em>
Answer:
Exit velocity m/s.
Explanation:
Given:
At inlet:
Properties of steam at 100 bar and 600°C
At exit:Lets take exit velocity
We know that if we know only one property inside the dome then we will find the other property by using steam property table.
Given that dryness or quality of steam at the exit of nozzle is 0.85 and pressure P=80 bar.So from steam table we can find the other properties.
Properties of saturated steam at 80 bar
So the enthalpy of steam at the exit of turbine
Now from first law for open system
In the case of adiabatic nozzle Q=0,W=0
m/s
So Exit velocity m/s.